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uysha [10]
3 years ago
10

I need help this stuff is difficult.

Mathematics
1 answer:
timama [110]3 years ago
7 0

Answer:

Answer choice C

Step-by-step explanation:

The arc cosine of -0.65 is about 2.278 radians, which rounds to 2.28 or answer choice C. Hope this helps!

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Find the area of the shaded region.
valentina_108 [34]

Answer:

Area of the circle= π(27.8²)

Step-by-step explanation:

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3 years ago
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PLEASE PLEASE HELP!! THANK YOU
Dmitrij [34]

Step-by-step explanation:

17². + 144²=x²

289 + 20736=x²

x²=21025

x =√21025

x=145

145 miles apart

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2 years ago
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Aiyanah made 12 withdrawals of $175.25 each from her bank account. Then she made 17 deposits of $235.66 to her same account that
Nonamiya [84]

Answer:

The overall change is $1903.22

Step-by-step explanation:

Let us approach this problem step wise

1.Firstly let us calculate all 12 withdrawal of $175.25

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2. Let us calculate all the deposits made 17* $235.66 = $4006.22

With these figures we can calculate the overall changes as

= $4006.22-$2103= $1903.22

3 0
3 years ago
CAn someone help with this question
polet [3.4K]

Answer: if the blue rectangles are x, then x = 1/2

1/2 + 1/2 = 1

the green shapes each = 1

so you have 1 + 1 + 1 = 3 which is true so

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Step-by-step explanation:

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3 years ago
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Find the MAD for this set of data.
Nostrana [21]

Answer:

Hence MAD=0.8

Step-by-step explanation:

<u>MAD-</u>

MAD is also known as Mean Absolute Deviation.

We find MAD by the following steps:

  • Firstly we find the mean of the data
  • Then we subtract each entry from the mean to obtain the deviation
  • Then find the absolute value of the deviation which is also known as absolute deviation.
  • Finally we find the mean of the absolute deviation.

Now we are given a table of the absolute deviation we just need to calculate the mean of the absolute deviation.

The absolute deviation is given as:

1    3    1    0    0    1    0    0    1    1

The mean of this is calculated as:

\dfrac{1+3+1+0+0+1+0+0+1+1}{10}=\dfrac{8}{10}=0.8

Hence, MAD=0.8




7 0
3 years ago
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