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AysviL [449]
3 years ago
11

What does paragraph 26 reveal about Rachel's character?

Mathematics
1 answer:
4vir4ik [10]3 years ago
5 0

Answer:

your answer is A hope this helps

Step-by-step explanation:

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Y = 4x + 3 how do you solve this
laiz [17]

Answer:

You cannot gather an answer from this, it is in simplest form

5 0
3 years ago
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F(x) = 2x2 - 5<br> and<br> g(x) = 5x + 7<br> Find<br> f(g(x)) = [ ? ]x2 + [ ]x +
lbvjy [14]

Answer:10x^2 -18

Step-by-step explanation:since f(x) is becoming the new x then youd subtitute the equation into the x of the g(x) equation. which would be 5(2x^2 -5) +7 which is 10x^2 -25 +7.and you'd simplify from there.

8 0
3 years ago
3. The bill at a restaurant
meriva

Answer:

$156.86

Step-by-step explanation:

$136.40 + 15% = $20.46

$136.40 + $20.46 = $156.86

3 0
3 years ago
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Mark wants to be a millionaire by the time he retires at age 65. He assumes there is a 6% annual interest rate. If he starts sav
Mashutka [201]

Answer:

B is the answer for this question. :)

Step-by-step explanation:


5 0
3 years ago
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Write an expression in factored form that is equivalent to the given expression. 1/2x + 4 . can u also tell how you solved it ?
Rufina [12.5K]
2 ways: Easy and hard
Hard=A
Easy=B
A: 1/2x+4 work from there so we do fun stuff with it make something that can be simplified so 1/2x+4 times (2/2)=x+8 now square the whole thing and put the result in a square root thingie (x+8)^2=x^2+16x+64 \sqrt{x^2+16x+64} multiply the whole thing by 4/4 and put \sqrt{16} [\tex] on top so then &#10;[tex] \sqrt{x^2+16x+64} times \frac{ \sqrt{16} }{4}=\frac{\sqrt{(16)(x^2+16x+64)}}{4}=\frac{ \sqrt{16x^2+256x+1024} }{4} to solve it, factor out the 16 in the square root and then square root 16 to get 4 then it will be (4 times square root of equation)/4=square root of equatio factor square root of equation and square root it and get x+8 divide by 2 to get 1/2x+4


B: 1/2x+4
put stuff that cancels out
1/2x+3x-3x+4+56-56
move them around
3 and 1/2x-3x+60-56
or
2x-3x+1 and 1/2x+30-20+30-36
then just add like terms to solve

5 0
3 years ago
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