Question

(2r - 6)(-5r+4) what is the product

Answer 1

Answer:

$-10r^{2} +38r-24$

Step-by-step explanation:

Apply FOIL method: $(a+b)(c+d)=ac+ad+bc+bd$

$a=2r,b=-6,c=-5r,d=4$

$=2r(5-r)+2r*4+(-6)(-5r)+(-6)*4$

Apply minus - plus rules

$+(-a)=-a,(-a)(-b)=ab$

$=-2*5rr+2*4r+6*5r-6*4$

Simplify

Multiply $-2*5rr=-10r^{2}$

$=-10r^{2} +2*4r+6*5r-6*4$

Multiply $2*4r=8r$

$=-10r^{2} +8r+6*5r-6*4$

Multiply $6*5r=30r$

$=-10r^{2} +8r+30r-6*4$

Combine like terms

$=-10r^{2} +38r-6*4$

Multiply $-6*4=-24$

$=-10r^{2} +38r-24$

$-10r^{2} +38r-24$