Answer:
Option 1.
Explanation:
To know which option is correct, let us calculate the net force in each case to know which will move to the right direction.
Option 1:
Force to the right (Fᵣ) = 8 N
Force to the left (Fₗ) = 6 N
Net force (Fₙ) =?
Fₙ = Fᵣ – Fₗ
Fₙ = 8 – 6
Fₙ = 2 N to the right
Option 2:
Force to the right (Fᵣ) = 8 N
Force to the left (Fₗ) = 10 N
Net force (Fₙ) =?
Fₙ = Fₗ – Fᵣ
Fₙ = 10 – 8
Fₙ = 2 N to the left
Option 3:
Force to the right (Fᵣ) = 10 N
Force to the left (Fₗ) = 10 N
Net force (Fₙ) =?
Fₙ = Fᵣ – Fₗ
Fₙ = 10 – 10
Fₙ = 0 (no movement)
Option 4:
Force to the right (Fᵣ) = 10 N
Force to the left (Fₗ) = 13 N
Net force (Fₙ) =?
Fₙ = Fₗ – Fᵣ
Fₙ = 13 – 10
Fₙ = 3 N to the left
From the illustrations made above, only option 1 has a net force toward the right direction. Therefore, only option 1 will have an acceleration towards the right direction.
Answer:
<h2>To solve typical questions like this we can use law of conversation of linear momentum...which is</h2>
<h2>T.I.L.M.=T.F.L.M.</h2>
(Total initial linear momentum = total final linear momentum.)
<u>Momentum = mass × velocity</u>
<h2>T.I.L.M = T.F.L.M</h2>
180×4 + 120×0 = 180×0 + 120×V
(180 ×4)/120 = V
<h2>6Ms^-1 = v</h2>
25g becoz acceleration is inversely to the mass when force is constant
To solve this problem it is necessary to apply the concepts related to the continuity of fluids in a pipeline and apply Bernoulli's balance on the given speeds.
Our values are given as
From the continuity equations in pipes we have to
Where,
= Cross sectional Area at each section
= Flow Velocity at each section
Then replacing we have,
From Bernoulli equation we have that the change in the pressure is
![7.3*10^3 = \frac{1}{2} (1000)([ \frac{(1.25*10^{-2})^2 }{0.6*10^{-2})^2} v_1 ]^2-v_1^2)](https://tex.z-dn.net/?f=7.3%2A10%5E3%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%281000%29%28%5B%20%5Cfrac%7B%281.25%2A10%5E%7B-2%7D%29%5E2%20%7D%7B0.6%2A10%5E%7B-2%7D%29%5E2%7D%20v_1%20%5D%5E2-v_1%5E2%29)
Therefore the speed of flow in the first tube is 0.9m/s
