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Thepotemich [5.8K]
3 years ago
13

Which of the following is not a compound A. Gold B. Water C. Salt D. Sugar

Physics
1 answer:
skelet666 [1.2K]3 years ago
6 0

Answer:

Gold

Explanation:

Water is H20

Salt is NaCl

Sugar is C12H22O11

Gold is Au with no other elements

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According to Newton's Third Law of Motion, what happens when two objects of unequal masses collide?
maksim [4K]
<span>Newton's third law is that for every action, there is an equal and opposite reaction.
A </span><span>Damage is not a part of physics, at least I don't think it is. </span><span>
B </span>Is just downright wrong. If anything, the smaller mass will be pushed forward with the heavier mass. <span>
C Sounds correct
D It'</span><span>s wrong, because the masses are not equal, or else they would stop.</span>
8 0
3 years ago
Below is an "oracle" function. An oracle function is a function presented interactively. When you type in a t value, and press t
Bingel [31]

Answer:

The rate of change of height with respect to time is -10.64 feet/sec

Explanation:

Given that,

There are three lines, so you can calculate three different values of the function at one time.

The function f(t) represents the height in feet of a ball thrown into the air, t seconds after it has been thrown.

Given table is,

Time t = 0, 1, 1,02

Function is,F(t)=-3.053113177191196\times10^{-18},6.000000000000134, 6.41760000000015

We need to calculate the initial height of ball

Using equation of motion

h=h_{0}+ut-\dfrac{1}{2}gt^2

Where, h₀ = initial height

u = initial velocity

t = time

g = acceleration due to gravity

At t = 0,

Put the value into the formula

-3.053113177191196\times10^{-18}=h_{0}+0-0

h_{0}=-3.053113177191196\times10^{-18}

We need to calculate the height of ball at t = 1

Using equation of motion

h_{1}=h_{0}+u_{0}t-\dfrac{1}{2}gt^2

Put the value in the equation

6.000000000000134=-3.053113177191196\times10^{-18}+u-\dfrac{1}{2}\times32

6.000000000000134+3.053113177191196\times10^{-18}+16=u_{0}

u_{0}=22\ feet/s

Velocity is the rate of change of height with respect to time

So, velocity at 1.02 sec is given

We need to calculate the height

Using equation of motion

h=ut-\dfrac{1}{2}gt^2

On differentiating w.r.to t

h'(t)=u-\dfrac{1}{2}g(2t)

Put the value into the formula

h'(t)=22-\times32\times(1.02)

h'(t)=-10.64\ feet/sec

Hence, The rate of change of height with respect to time is -10.64 feet/sec.

4 0
3 years ago
Please help! I especially need help with the second question but help with the first one would be most appreciated!
lara31 [8.8K]

Answer:

a) Team A will win.

b) The losing team will accelerate towards the middle line with 0.01 m/s^{2}

Explanation:

Given that Team-A pulls with a force , F_{1} = 50N

and Team-B pulls with a force , F_{1} = 45N

∵ F_{1} > F_{2}

The rope will move in the direction of force F_{1}.

∴ Team-A will win.

b) Considering both the teams as one system of total mass , m = 246+253 = 499 kg

Net force on the system , F = F_{1} - F_{2} = 50-45 = 5N

Applying Newtons first law to the system ,

F = ma , where 'a' is the acceleration of the system.

Since , both the teams are connected by the same rope , their acceleration would be the same.

∴ 5 = 499×a

∴ a = 0.01 m/s^{2}

4 0
3 years ago
Please help me**** i need some answers now
sweet-ann [11.9K]
Output can not be greater than input because the conversion of energy can not be greater than 100%.
4 0
3 years ago
An iron railroad rail is 800 ft long when the temperature is 31°C. What is its length (in ft) when the temperature is −17°C?
natta225 [31]

Answer:

799.54 ft

Explanation:

Linear thermal expansion is:

ΔL = α L₀ ΔT

where ΔL is the change in length,

α is the linear thermal expansion coefficient,

L₀ is the original length,

and ΔT is the change in temperature.

Given:

α = 1.2×10⁻⁵ / °C

L₀ = 800 ft

ΔT = -17°C − 31°C = -48°C

Find: ΔL

ΔL = (1.2×10⁻⁵ / °C) (800 ft) (-48°C)

ΔL = -0.4608

Rounded to two significant figures, the change in length is -0.46 ft.

Therefore, the final length is approximately 800 ft − 0.46 ft = 799.54 ft.

7 0
3 years ago
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