Any object that is launched as a projectile will lose speed and, as a result, altitude, as it travels through the air. The rate at which the object loses speed and altitude depends on the amount of force that way applied to it when it was launched. It is also dependent on the size and shape of the item. This is why something like, say, a football is much faster to fall to the ground than a bullet.
Explanation:
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Answer:
Distance S = 11.77 m (Approx.)
Explanation:
Given:
Time t = 1.55 Second
Gravity acceleration = 9.8 m/s²
Find:
Distance S
Computation:
S = ut + (1/2)(g)(t)²
S = (0)(1.55) + (1/2)(9.8)(1.55)²
S = (0)(1.55) + (1/2)(9.8)(1.55)²
Distance S = 11.77 m (Approx.)
Answer:
The distance d from the car at which the sound from the stereo can still be discerned = 97720.5 m
Explanation:
Sound intensity heard at distance is related to the distance with the relation = (power of sound at the source)/(surface area of the wall of an imaginary sphere at the distance in question)
I = P/4πd²
Assuming the car has 2 speakers,
P = 0.06 W × 2 = 0.12 W
d = ?
For the intensity of the least discernible sound,
I = 10⁻¹² W/m²
10⁻¹² = 0.12/4πd²
d = 97720.5 m
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