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Valentin [98]
3 years ago
14

Please be quick i need this as soon as possible!

Mathematics
1 answer:
Hoochie [10]3 years ago
6 0

Answer:

120 tickets

Step-by-step explanation:

1/2 of 80 is 40. you take 40 and multiply it by 2 and then multiply 40 again by 1. It would then be 80 tickets and 40 tickets. This would result in 120 tickets given out.

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Solving a _____ is the process of calculating unknown side lengths or angle measures of a triangle if certain of the side length
Ray Of Light [21]
ANSWER

C) Triangle

EXPLANATION

Solving a triangle is the process of calculating unknown side lengths or angle measures of a triangle if certain of the side lengths and/or angle measures are known.

We use the sine rule and cosine rule to find the missing sides and angles.

If the triangle has a right angle, then this is a special case, where we can use the trigonometric ratios and the Pythagoras theorem to find the unknown angles and sides.
6 0
3 years ago
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Find the point on the line y=2x that is closest to the point (4, 5) .
alexgriva [62]
That point would be : (2.5,5)
7 0
3 years ago
What is the length of the rectangular prism if it has a width of 13 meters, a helght of 17 meters, and a volume of 2,873
pentagon [3]

Answer:

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Step-by-step explanation:

v = lwh \\  \\ 2873 = l(13)(17) \\ 2873 = 221l \\ l = 2873  \div 221 \\ l = 13

6 0
3 years ago
Please help me on number 4
Mariulka [41]
Angle 5 = 117° because it is vertical to angle 8
Angle 7 = 63° because it is symmetrical to angle 5
Angle 6 = 63° because it is vertical to angle 7.
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Angle 2 = 63° because it is corresponding to angle 6.
Angle 3= 117° because it is corresponding to angle 8.
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3 0
3 years ago
What is the greatest common factor of 45x^3, 24x^2, and 16x?
Phoenix [80]

Answer:

\huge\boxed{\sf GCF = x}

Step-by-step explanation:

<u>Firstly we'll factorize the terms:</u>

45x³ = 3 * 3 * 5 * x * x * x

24x² = 2 * 2 * 2 * 3 * x * x

16x = 2 * 2 * 2 * 2 * x

<u>The factor which is common in all three terms is:</u>

= x

Hence GCF = x

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
8 0
2 years ago
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