All categories

3 years ago

What is the value of b when the expression-6.2x + b is equivalent to -3.1(2x - 3)

Mathematics

1 answer:

Rudik [331]3 years ago

8 0

Answer:

$- 6.2x + b \equiv - 3.1(2x - 3) \\ - 6.2x + b = - 6.2x + 9.3 \\ b = 9.3$

You might be interested in

You are going to use an inclined plane to lift a heavy object to the top of a shelving unit with a height of 6 feet. The base of

Mama L [17]

24000 is the answer

3 0

3 years ago

I have no clue how to do this. I just need to pass my online math class.

Lerok [7]

If F(3) then 3=x. So all you would do is substitute 3 in for x

3 0

3 years ago

Read 2 more answers

Cheryl collected data for her mathematics project. She noted that the data set was approximately normal.

nadya68 [22]

Answer:

$X_(r) >> X_(n)$

The mean for this case would increase since is defined as:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

The interquartile range would not change since the definition for the IQR is $IQR =Q_3 -Q_1$ and the quartiles are the same.

The standard deviation would not remain the same since by definition is:

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And since we change the largest value the deviation would increase considerably.

And for the last option is not always true since if we select a value so much higher then the distribution would be skewed to the right.

So the best option for this case is:

Mean would increase.

Step-by-step explanation:

For this case we assume that we have a random sample given $X_(1), X_(2) ,..., X_(n)$ and for each observation $X_i \sim N(\mu, \sigma)$ since the problem states that the data is approximately normal.

Let's assume that the largest value on this sample is $X_(n)$ and for this case we are going to replace this value by another one extremely higher so we satisfy this condition:

$X_(r) >> X_(n)$

The mean for this case would increase since is defined as:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

The interquartile range would not change since the definition for the IQR is $IQR =Q_3 -Q_1$ and the quartiles are the same.

The standard deviation would not remain the same since by definition is:

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And since we change the largest value the deviation would increase considerably.

And for the last option is not always true since if we select a value so much higher then the distribution would be skewed to the right.

So the best option for this case is:

Mean would increase.

6 0

3 years ago

ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. Show your work OR give an explaination.

love history [14]

Answer:

$\boxed{D. 3 {x}^{2} - x - 6}$

Given:

$f(x) = 3{x}^{2} - 4 \\ \\ g(x) = x + 2$

To Find:

$(f - g)(x) = f(x) - g(x)$

Step-by-step explanation:

$= > f(x) - g(x) = (3{x}^{2} - 4) - (x + 2) \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3{x}^{2} - 4 -(x) - (2)\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =3{x}^{2} - 4 - x - 2\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =3 {x}^{2} - x - 6$

8 0

3 years ago

Data were collected on the number of days per week that members visit a certain fitness center. The values varied from 0 to 7, a

aleksley [76]

Answer: D

Step-by-step explanation:

6 0

3 years ago