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grigory [225]
3 years ago
7

Write the quadratic equation whose roots are 2 and -2, and whose leading coefficient is 4

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
8 0

Answer:

4x^2-16=0

Step-by-step explanation:

We want to write the quadratic equation whose roots are 2 and -2, and whose leading coefficient is 4.

Since 2 and -2 are roots,   x+2\\and\\x-2  are factors of this quadratic function.

The factored form is given as: a(x-2)(x+2)=0

Since the leading coefficient is 4, a=4

Therefore the equation becomes:

4(x-2)(x+2)=0

Recognize and expand using difference two squares.

4(x^2-4)=0

The required equation is:

4x^2-16=0

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\large\displaystyle\text{$\begin{gathered}\sf \frac{2x-20}{3}=2x  \end{gathered}$}

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\large\displaystyle\text{$\begin{gathered}\sf 2x-20=6x \end{gathered}$}

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\large\displaystyle\text{$\begin{gathered}\sf x=-5 \ \ \to \ \ \ Answer \end{gathered}$}

<h2>{ Pisces04 }</h2>
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