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zaharov [31]
4 years ago
10

What is the unit rate of 400 miles for 20 gallons?

Mathematics
1 answer:
aleksklad [387]4 years ago
5 0
Answer: 400 / 20 = 20
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4. Nine fruit juice bottles contain 4 1/2 litres of fruit juice between them.
brilliants [131]

Answer:

2\frac{1}{2} litres or 2.5 litres

Step-by-step explanation:

From the question, 9 fruit juice bottles contain 4\frac{1}{2} litres of fruit juice. Therefore, to find how many litres of fruit juice would be contained in 5 fruit juice bottles, you multiply 5 by 4\frac{1}{2} litres and you divide the product by 9.

i.e. Let the quantity of the fruit juice for 5 bottles be x.

9 juice bottles ===> 4\frac{1}{2} litres

5 juice bottles ===> x

∴x = \frac{5 * 4\frac{1}{2} }{9} litres

x = \frac{5 * 4.5}{9} litres

x = \frac{22.5}{9} litres

x = 2.5 litres or 2\frac{1}{2} litres

Hope this helps!!!

3 0
3 years ago
How much money at 12 weeks?<br><br>1). 330<br>2). 290<br>3). 360
zloy xaker [14]

To answer this question, you need to write a linear equation (because the graph is a visibly straight line) that models this situation, then plug in 12.

The general format for a linear equation is y=mx+b, where m is the slope and b is the y intercept.  The y intercept of a line is where it crosses the y axis; for this line, it crosses the y axis at (0, 0) so the y intercept is 0.

To find the slope, use the slope equation: (y2-y1)/(x2-x1).  For y1, y2, x1, and x2, just pick any two points on the line.  We will use (1, 30) and (2, 60):

(60-30)/(2-1)

30/1

30

The line is y=30x.

Plug in 12 for x:

y=30(12)

y=360

3). 360

Hope this helps!!

3 0
3 years ago
The formula f=5280m can be used to convert a measurement of f feet to an equivalent measurement m miles. If an airplane flies at
enot [183]
The answer is a
21,120/5280=4
4 0
3 years ago
a volley ball player servers the ball. The ball follows a path given by the equation y=-0.01x^2+0.5x+3 where x and y are measure
dolphi86 [110]

Answer:

(a)

Distance from player should be 13.82 feet or 36.2 feet

(b)

The ball will go over the net

Step-by-step explanation:

we are given

The ball follows a path given by the equation

y=-0.01x^2+0.5x+3

where

x and y are measured in feet and the origin is on the court directly below where the player hits the ball

(a)

net height is 8 ft

so, we can set y=8

and then we can solve for x

8=-0.01x^2+0.5x+3

8\cdot \:100=-0.01x^2\cdot \:100+0.5x\cdot \:100+3\cdot \:100

800=-x^2+50x+300

-x^2+50x-500=0

x^2-50x+500=0

we can use quadratic formula

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\frac{-50\pm \sqrt{50^2-4\left(-1\right)\left(-500\right)}}{2\left(-1\right)}

x=5\left(5-\sqrt{5}\right),\:x=5\left(5+\sqrt{5}\right)

x=13.82,x=36.2

So, distance from player should be 13.82 feet or 36.2 feet

(b)

we can plug x=30 and check whether y=8 ft

y=-0.01(30)^2+0.5(30)+3

y=9ft

we know that

height of net is 8 ft

so, the ball will go over the net


5 0
4 years ago
Let g(x)=x-3 and h(x)=x^2+6 find (h o g) (1)
cupoosta [38]
g(x)=x-3 \ \ \ and\ \ \  h(x)=x^2+6 \\\\(h \circ  g) (1)=h\bigg (g(1)\bigg)=h\bigg(1-3\bigg)=h(-2)=(-2)^2+6=4+6=10
5 0
3 years ago
Read 2 more answers
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