Which line segment is congruent to BC? GEOMETRY HELP PLS!!!
2 answers:
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Answer:
Step-by-step explanation:
we have
Solve the quadratic equation to find the zero's or x-intercepts
Remember that
The x-intercepts are the values of x when the value of y is equal to zero ( water balloon reach the ground)
we know that
The formula to solve a quadratic equation of the form is equal to
in this problem we have
so
substitute in the formula
therefore
the solution is
Discussion
1. Put brackets around the first two terms
y = (-x^2 + 6x) + 5
2. Take out the common factor of -1
y = -(x^2 - 6x) + 5
3. Inside the brackets, take 1/2 of - 6 and square it
y = -(x^2 - 6x + ( - 6 / 2)^2 ) + 5
y = -(x^2 - 6x + (- 3)^2 ) ) + 5
y = -(x^2 - 6x + 9 ) + 5
Note: Step 3 is very long. Make sure you work your way through it
4. You have added 9 inside the brackets. <em><u>It is actually - 9. So add 9 outside to balance the equation out. </u></em> This is the key step. Make sure you understand it.
y = - (x^2 - 6x + 9) + 5 + 9
5. Express the brackets as a square.
y = - (x + 3)^2 + 14
Discussion
The equation is now in vertex form. The minus tells you that the equation is a maximum. The maximum is located at ( - 3, 14 )
A graph follows to show the results.
