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makvit [3.9K]
3 years ago
13

See screenshot...need help its due today

Mathematics
1 answer:
Pani-rosa [81]3 years ago
4 0

Answer:

Step-by-step explanation:

f=20

Im a god bro

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A system contains n atoms, each of which can only have zero or one quanta of energy. How many ways can you arrange r quanta of e
My name is Ann [436]

Answer:

\mathbf{a)} 2\\ \\ \mathbf{b)} 184 \; 756 \\ \\\mathbf{c)}  \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}

Step-by-step explanation:

If the system contains n atoms, we can arrange r quanta of energy in

                         \binom{n}{r} = \dfrac{n!}{r!(n-r)!}

ways.

\mathbf{a)}

In this case,

                                n  = 2, r=1.

Therefore,

                    \binom{n}{r} = \binom{2}{1} = \dfrac{2!}{1!(2-1)!} = \frac{2 \cdot 1}{1 \cdot 1} = 2

which means that we can arrange 1 quanta of energy in 2 ways.

\mathbf{b)}

In this case,

                                n  = 20, r=10.

Therefore,

                    \binom{n}{r} = \binom{20}{10} = \dfrac{20!}{10!(20-10)!} = \frac{10! \cdot 11 \cdot 12 \cdot \ldots \cdot 20}{10!10!} = \frac{11 \cdot 12 \cdot \ldots \cdot 20}{10 \cdot 9 \cdot \ldots \cdot 1} = 184 \; 756

which means that we can arrange 10 quanta of energy in 184 756 ways.

\mathbf{c)}

In this case,

                                n = 2 \times 10^{23}, r = 10^{23}.

Therefore, we obtain that the number of ways is

                    \binom{n}{r} = \binom{2\times 10^{23}}{10^{23}} = \dfrac{(2\times 10^{23})!}{(10^{23})!(2\times 10^{23} - 10^{23})!} = \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}

3 0
3 years ago
?????????!??!!?!?!?!?!?!?!?
vivado [14]

Answer:

Option 4:  y > 2x

                x + 2y < -8

Step-by-step explanation:

Taking first equation:

y > 2x

Putting x = 0

y > 0

Putting y = 0

0 > x

So the blue line in drawn according to first equation.

Taking second equation:

 x + 2y < -8

Putting x = 0

 2y < -8

y < - 4

putting y = 0

 x < -8

So the red line is drawn accordingly.

i hope it will help you!

7 0
3 years ago
A line passes through the point (-4,-5) and had a slope of 5/2. Write an equation in slope-intercept form
daser333 [38]

Step-by-step explanation:

as we have a point and the slope, we can start with the point-slope form and then transform.

the point-slope form is

y - y1 = a(x - x1)

(x1, y1) being a point on the line, a being the slope.

the slope-interceot form is

y = ax + b

a being the slope again, b being the y-intercept (the y value for x = 0).

so, we have

y - -5 = 5/2 × (x - -4)

y + 5 = 5/2 × (x + 4) = 5x/2 + 5×4/2 = 5x/2 + 10

y = 5x/2 + 5

or

y = (5/2)x + 5

and this is already the slope-intercept form. all done.

4 0
2 years ago
Brainliest to right answer...
satela [25.4K]
the slope is -2

have a nice day :D
8 0
3 years ago
Which of the following ratios is equivalent to 24:36?
Ksju [112]

Answer:

D, 20:30

Step-by-step explanation:

At first glance, this does not seem like the correct ratio. But I'll spare you a long intro and get into it:

20:30: Divide both of them by 10

=2:3

2 x 12:3 x 12

24:36

Hope this helps!

4 0
3 years ago
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