If log65 = 1.812 what is the value of log(base 1000)65 ? 0.0604 0.604 0.1812 0.001812
1 answer:
If we have:
logₐy = (logₓy) / (logₓa) By change of base formula.
log₁₀65 = (log₁₀₀₀65) / (log₁₀₀₀10)
(log₁₀₀₀65) = log₁₀65 * (log₁₀₀₀10)
log(₁₀₀₀10) = 1/ (log₁₀1000) = 1/(log₁₀10³) = 1/3
(log₁₀₀₀65) = (log₁₀65) * (log₁₀₀₀10)
(log₁₀₀₀65) = 1.812 * (1/3)
(log₁₀₀₀65) = 0.604
I hope this helps.
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