If log65 = 1.812 what is the value of log(base 1000)65 ? 0.0604 0.604 0.1812 0.001812

1 answer:

ioda3 years ago

8 0

If we have:

logₐy = (logₓy) / (logₓa) By change of base formula.

log₁₀65 = (log₁₀₀₀65) / (log₁₀₀₀10)

(log₁₀₀₀65) = log₁₀65 * (log₁₀₀₀10)

log(₁₀₀₀10) = 1/ (log₁₀1000) = 1/(log₁₀10³) = 1/3

(log₁₀₀₀65) = (log₁₀65) * (log₁₀₀₀10)

(log₁₀₀₀65) = 1.812 * (1/3)

(log₁₀₀₀65) = 0.604

I hope this helps.

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