If the area (in square units) of the region under the curve of the function f(x) = 3x − 1 on the interval [a, 4], where a < 4
, is 12 square units, identify all the possible values of a.
-3
0
-16/5
8/3
-2
7/2
1 answer:
Answer:
Step-by-step explanation:
The integral from a to 4 is ...

We want the value of this to be 12, so we can write ...
-3/2a^2 +a +20 = 12
3a^2 -2a -16 = 0 . . . . . subtract the left side and multiply by 2
(3a -8)(a +2) = 0 . . . . . factor
a = 8/3 or -2 . . . . . . . .values of a that make the factors zero
The only possible values of a are 8/3 and -2.
You might be interested in
No they are not… not the same size
Answer:
1072.3
Step-by-step explanation:
V=(2/3)πr³ is the formula.
-hope it helps
Answer:
bbbbbbbbbnbbbb bbbbbbbbbb
Volume =
150 =
x 3.14 x 10 x 10 x h
150 x 3 = 314 x h
h = 450/314
h = 1.43 inches