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Vaselesa [24]
3 years ago
6

Solve the equation. IM 4=t/2.5

Mathematics
1 answer:
m_a_m_a [10]3 years ago
3 0

Answer:

t=10

Step-by-step explanation:

4=t/2.5

4=t/25/10

divide 25and10 by 5=5/2

4=t/5/2

4=t×2/5

multiply both sides of the equation by 5

5×4=t×2/5×5

20=t×10/5

20=t×2

— —

2. 2

10=t

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How high up on a wall does a 50 ft ladder reach if the bottom of the ladder is placed 14 ft from the base of the building
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Answer:

48 ft

Step-by-step explanation:

7 0
4 years ago
Find the measure of FEG 25,65,80,90
lozanna [386]

Answer:

First, you have to set 5x equal to (3x+10). They are vertical angles and therefore congruent.

5x = 3x+10              The variable should only be on one side of the equation,

5x - 3x = 10             Therefore subtract 3x from both sides

2x = 10                     Divide by 2 on both sides.

x = 5

We're not done yet, since we've found the x-value we have to solve for ∠GEC.

∠GEC = 3x+10 = 3(5)+10 = 15+10 = 25°

∠GEC and ∠FEG form a right angle. This means that the sum of the two angles is 90°

90° = 25° + x            In this case, we're using "x" to solve for ∠FEG

90-25 = x                  We subtract 25 from both sides to get the variable by itself.

65° = x

∠FEG = 65°            The Answer is B

Step-by-step explanation:

7 0
3 years ago
The town of lantana needs $14,000 for a new playground. lantana elementary school raised $5358 lantana middle school raised $283
Arada [10]
Total money needed = $14,000
Total money collected = $5358+$2834+4132 = $12324

Additional money needed = Total money - Money collected

=> $14,000 - $12,324
=> $1,676

So they need $1676 more money to be collected
7 0
3 years ago
A college is creating a new rectangular parking lot. the length is 0.17 mile longer than the width and the area of the parking l
Svetradugi [14.3K]
Let's call the width of the parking lot w.
The length of the parking lot if .17 more than the width so the length is w + .17

The parking lot is rectangular so its area is found by multiplying the length and the width. That is, the area is equal to what we obtain when we multiply w by w+.17. The area is: A = w(w+.17)= w^{2} +.17w

We are also told that the area is equal to .039 square miles so we set the expression we obtained for the area equal to .039 as follows.

w^{2} +.17w=.039

Since w represents the width of the rectangular lot, we can solve this equation for w to find the width. This is a quadratic equation (the highest exponent of the variable w is 2). We solve these by setting them equal to zero and then using the quadratic formula.

Setting our equation equal to zero (subtract .039 from both sides) gives us:
w^{2} +.17w-.039=0

The quadratic formula is as follows. Since the equation is in terms of w we write it as "w = ..." instead of the usual "x = ..."

w= \frac{-bplusminus \sqrt{ b^{2} -4ac} }{2a}

The part I write as "plusminus" is typically written with a + sign over a - sign. For right now let's leave it at that. Later in the problem we will see what it means and what to do with it.

To use the formula we have to identify a, b and c.

a is the coefficient of the squared term. That is, the number in front of w^{2} which here is 1.

b is the coefficient of the linear term. That is, the number in front of w which here is .17

c is the constant (the number by itself0 which is -.039

So we have:
a=1
b=.17
c=-.039

We plug these into the quadratic formula to obtain:
w= \frac{-.17plusminus \sqrt{ .17^{2} -(4)(1)(-.039)} }{(2)(1)}
w= \frac{-.17plusminus \sqrt{ .0289+.156} }{2}
w= \frac{-.17plusminus \sqrt{ .189} }{2}
w= \frac{-.17plusminus.43} {2}

Here is where the "pluminus" comes in. We continue to simplify the expression on the right but we split it in two. In one case we use "plus" and in the other "minus". That is, we add in one and subtract in the other. This gives us:
w= \frac{-.17+.43}{2}= \frac{.26}{2}=.13
and
w= \frac{-.17-.43}{2}= \frac{-.6}{2}=-.3

w is the width of the rectangular lot so it is a distance and cannot be measured using negative numbers. The width of the rectangular must be positive so we disregard the negative answer.

The width of the rectangle is .13 miles

Recall that the length of the rectangle is .17 more than the width. That is, the length is w+.17 and as we know the width to be .13 miles the length is .13 + .17 = .3 miles

The answer therefore is:
width = .13 miles
length = .3


4 0
3 years ago
Read 2 more answers
What is the factored expression of 56n - 70?
mart [117]

Answer:

14(4n - 5)

Step-by-step explanation:

The GCF of 56 and 70 is 14

56/14 = 4

70/14 = 5

Place the GCF outside the parenthesis

14(

and keep the n on 56 and put it on 14, = 14n,

14(4n

then keep the subtraction sign and 5 and put it in the parenthesis

14(4n - 5)

i hope that maked sense and helped you! (and could i have brainliest if possible it would really help me!)

5 0
3 years ago
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