The two pairs are Pythagorean triples because if you plug the two legs of a right triangle into the Pythagorean theorem(A^2+B^2=C^2), then you will find the measurement for the third side(hypotenuse). i.e. 15^2+12^2=9^2(it's the Pythagorean triple 3,4,5 multiplied by 3). This works with any triple, as long as your using the legs of the triangle and as long as the triangle is a right triangle.
90 degrees less. (I’m just getting started)
Answer is x-1/3x^2
Merry Christmas
The answer i came up with is : (4b-7x) (a+2)
Answer: 140 ![in^{2}](https://tex.z-dn.net/?f=in%5E%7B2%7D)
Step-by-step explanation:
The area for a trapeziod is A =
(b1+b2)h
We have almost everything we just need the total length of the top base, since it gives us the outer lengths we can find that by simply doing 4+6+15 which turns out to be 25
Now we can plug in our values:
A =
(25 + 15) x 7 = 140![in^{2}](https://tex.z-dn.net/?f=in%5E%7B2%7D)