Question

In his explanation of the threshold frequency in the photoelectric effect, Einstein reasoned that the absorbed photon must have a minimum energy to dislodge an electron from the metal surface. This energy is called the work function (φ) of the metal. Many calculators use photocells to provide their energy. Find the maximum wavelength needed to remove an electron from silver (φ = 7.59 × 10 −19 J).

Answer 1

Answer:

$\lambda = 260.9nm$

Explanation:

As we know that work function is defined as the minimum energy of photons required to produce the photo electric effect

so here we have

$\phi = \frac{hc}[\lambda}$

now we know that

$h = 6.63\times 10^{-34}$

$c = 3\times 10^8 m/s$

$\lambda$ = wavelength of photons

now from above formula

$7.59 \times 10^{-19} = \frac{(6.36 \times 10^{-34})(3\times 10^8)}{\lambda}$

$\lambda = \frac{(6.36 \times 10^{-34})(3\times 10^8)}{7.59 \times 10^{-19}}$

$\lambda = 260.9nm$