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Nana76 [90]
3 years ago
7

A 4500 kg Honda Civic, a 0.5 kg Matchbox car, and a 45 kg Power Wheel

Physics
1 answer:
Gemiola [76]3 years ago
6 0
F= ma so rearrange the equation to a= F/m (net force/ mass) and using that equation with all three different cars, the matchbox car has the greatest acceleration of 60 m/s^2
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Certain suv ads claim that their vehicles can climb a slope of 45?. what is the minimum coefficient of static friction between t
kotykmax [81]
First, you make a force body diagram to illustrate the problem. Then, apply Newton's laws of motion.

Summation of forces along the y-direction:

F = 0 (bodies at equilibrium) = Normal force - weight*cos45 = 0
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Summation of forcesalong the x-direction:

F = 0 (bodies at equilibrium) = Frictional force - weight*sin45 = 0
x*Normal force - weight*sin45 = 0   (let x be the min coeff of static friction)
x*weight*cos45 = weight*sin 45
x = sin45/cos45 = 1

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3 years ago
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7 0
4 years ago
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Firlakuza [10]

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5 0
4 years ago
I'm very confused. Thanks for whoever helps me :)
sergij07 [2.7K]
(C). Remember gravity provides an acceleration of 9.81m/s^2, so the y component of velocity initial is zero because it isn’t already falling, and we have the height, so basically we use the kinematic equation vf^2=vi^2+2ad, substitute given values and you get vf^2=2(9.81)(65) which is 1275, when you take the square root you get 35.7m/s for final velocity
(B). Then you use vf=vi+at to get the equation 35.7=(9.81)t, when you divide out you get 3.64s for time t
(A). Finally, since we assume that there is no acceleration or deceleration horizonatally, we just multiply the time taken for it to hit the ground and the initial speed ((3.64)(35.7)) to get 129.96, with significant figures I would round that to 130 metres.
**this is in the order that I felt was easiest to answer**
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3 years ago
How does the force of gravity between two bodies change when the distance between them doubles? 1. unable to determine; the mass
Rzqust [24]
6. Drop to one quarter of its original value
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3 years ago
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