Explanation:
Let
are the number of turns in primary and secondary coil of the transformer such that,

A resistor R connected to the secondary dissipates a power 
For a transformer, 

...............(1)
The power dissipated through the secondary coil is :


.............(2)
Let
are the new number of turns in primary and secondary coil of the transformer such that,

New voltage is :

...............(3)
So, new power dissipated is 





So, the new power dissipated by the same resistor is 6400 watts. Hence, this is the required solution.
For the purpose we will use the following equation for potential energy:
U = m * g * h
In the above equation, m represents the mass of the object, h represents the height of the object and g represents the gravitational field strength (9.8 N/kg on Earth).
When we plug values into the equation, we get following:
U= 65.7kg * 9.8 N/kg *135m = 86921.1 J = 86.92 kJ
The gravitational pull is weaker.
Answer:
511.545 Newtons
Explanation:
So 1 pound=4.44822 Newton’s so 115 times 4.44822 is 511.5453, then round it to get 511.545 Newtons.
(5 bulbs) x (25 watt/bulb) x (6 hour/day) x (30 day/month) =
(5 x 25 x 6 x 30) watt-hour/month =
22,500 watt-hour/month .
The most common unit of electrical energy used for billing purposes
is the 'kilowatt-hour' = 1,000 watt-hours .
22,500 watt-hour/month = <em>22.5 kWh/month</em>.
(22.5 kWh/month) x (1.50 Rs/kWh) = <em>33.75 Rs / month
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