Ask question

Ask question

All categories

3 years ago

7

In a LRC circuit, a second capacitor is connected in parallel with the capacitor previously in the circuit. What is the effect o

f this change on the impedance of the circuit

1 answer:

likoan [24]3 years ago

3 0

Answer:

Impedance increases for frequencies below resonance and decreases for the frequencies above resonance

Explanation:

See attached file

Explanation:

You might be interested in

Are the statements of the Flat Earth Society an example of science or pseudoscience?

Y_Kistochka [10]

Answer:

Pseudoscience

Explanation:

Pseudoscience is defined as set of ideas that present themselves as a science, but they do not fulfill the criteria to be called science. In the same way, in the middle of 20th century some people called earth is flat. They challenged the spherical shape of earth. But their hypothesis does not fulfill the criteria of science. Therefore, the statements of flat earth society are pseudoscience.

5 0

3 years ago

Read 2 more answers

The density of aluminum is 2.70 g/ml. A piece of aluminum foil has a mass of 44 g. What is the volume of this piece of aluminum

anyanavicka [17]

Answer:

C) 16.3 ml

Explanation:

Density is equal to the ratio between the mass of an object and its volume:

$d=\frac{m}{V}$

where

m is the mass

V is the volume

In our problem, we know:

- density of aluminium: $d=2.70 g/mL$

- mass of the aluminium foil: $m=44 g$

So we can re-arrange the equation above and use these data to find the volume of the piece of aluminium foil:

$V=\frac{m}{d}=\frac{44 g}{2.70 g/mL}=16.3 mL$

7 0

3 years ago

What magnitude charge creates a 1.0 n/c electric field at a point 1.0 m away?

Stolb23 [73]

Answer:

$1.1\cdot 10^{-10}C$

Explanation:

The electric field produced by a single point charge is given by:

$E=k\frac{q}{r^2}$

where

k is the Coulomb's constant

q is the charge

r is the distance from the charge

In this problem, we have

E = 1.0 N/C (magnitude of the electric field)

r = 1.0 m (distance from the charge)

Solving the equation for q, we find the charge:

$q=\frac{Er^2}{k}=\frac{(1.0 N/c)(1.0 m)^2}{9\cdot 10^9 Nm^2c^{-2}}=1.1\cdot 10^{-10}C$

8 0

3 years ago

A power plant produces 1000 MW to suply a city 40Km away.Current flows from the power plant on a single wire of resistance0.050

Westkost [7]

Answer:

The current in wire resistance 2Ω

a). 8696 A

b). fraction power 15.1% a 115kV

Explanation:

Resistance

$R=0.05$ Ω/Km*40km

R=2Ω

P=1000 MW

a).

$P=V*I\\I=\frac{P}{V}=\frac{1000x10^{6}W}{115x10^{3}k } =8696.65A$

Using law ohm

b).

$V=I*R\\I=\frac{V}{R}$

$P=I*I*R\\P=I^{2} *R\\P=8696.65^{2}*2\\P=151.228 x10^{6} W$

$e=\frac{151.228x10^{6} }{1000x10^{6} }*100= 15.12$ %

8 0

3 years ago

A student attaches a rope to his

erastova [34]

The choices are:

a. Normal Force

b. Gravity Force

c. Applied Force

d. Friction Force

e. Tension Force

f. Air Resistance Force

Answer:

The answer is letter e, Tension Force.

Explanation:

Force refers to the "push" and "pull" of an object, provided that the object has mass. This results to acceleration or a change in velocity. There are many types of forces such as <em>Normal Force, Gravity Force, Applied Force, Friction Force, Tension Force and Air Resistance Force.</em>

The situation above is an example of a "tension force." This is considered the force that is being applied to an object by strings or ropes. This is a type force that allows the body to be pulled and not pushed, since ropes are not capable of it. In the situation above, the tension force of the rope is acting on the bag and this allows the bag to be pulled.

Thus, this explains the answer.

6 0

3 years ago