In a LRC circuit, a second capacitor is connected in parallel with the capacitor previously in the circuit. What is the effect o
f this change on the impedance of the circuit
1 answer:
You might be interested in
Answer:
0.2 m
Explanation:
PHASE 1
First, we calculate the distance the tongue moved in the first 20 ms (0.02 secs). We use one of Newton's equations of linear motion:
where u = initial velocity = 0 m/s
a = acceleration =
t = time = 0.02 s
Therefore:
PHASE 2
Then, for the next 30 ms (0.03 secs), we use the formula:
This speed is the same as the final velocity of the tongue after the first 20 ms.
This can be obtained by using the formula:
Therefore:
distance = 5 * 0.03 = 0.15 m
Therefore, the total distance moved by the tongue in the 50 ms interval is:
0.05 + 0.15 = 0.2 m