Answer:
2
Step-by-step explanation:
<h3>
Answer: x = 7</h3>
Explanation:
Segment addition postulate
CD+DE = CE
this basically is the idea of gluing smaller pieces together to get a larger structure. We can go in reverse to break up a large item into smaller bits. This is assuming there is no leftovers, overlaps, or parts wasted/lost.
CD = 9
DE = 3x+6
CE = 36
----
CD+DE = CE
9+3x+6 = 36
3x+15 = 36
3x = 36-15
3x = 21
x = 21/3
x = 7
-----
If x = 7, then
DE = 3x+6 = 3*7+6 = 21+6 = 27
and
CD+DE = 9+27 = 36 = CE
confirming our answer
You first simplify the expression using PEMDAS
-2x^3-10x^2+2x^3-10x^2+x
then combine like terms,
(-2x^3+2x^3), (-10x^2-10x^2), x
cancels out^
so the answer would be -20x^2+x
This is a really interesting question! One thing that we can notice right off the bat is that each of the circles has the same amount of area swept out of it - namely, the amount swept out by one of the interior angles of the hexagon. Let’s call that interior angle θ. We know that the amount of area swept out in the circle is proportional to the angle swept out - mathematically
θ/360 = a/A
Where “a” is the area swept out by θ, and A is the area of the whole circle, which, given a radius of r, is πr^2. Substituting this in, we have
θ/360 = a/(πr^2)
Solving for “a”:
a = π(r^2)θ/360
So, we have the formula for the area of one of those sectors; all we need to do now is find θ and multiply our result by 6, since we have 6 circles. We can preempt this but just multiplying both sides of the formula by 6:
6a = 6π(r^2)θ/360
Which simplifies to
6a = π(r^2)θ/60
Now, how do we find θ? Let’s look first at the exterior angles of a hexagon. Imagine if you were taking a walk around a hexagon. At each corner, you turn some angle and keep walking. You make 6 turns in all, and in the end, you find yourself right back at the same place you started; you turned 360 degrees in total. On a regular hexagon, you’d turn by the same angle at each corner, which means that each of the six turns is 360/6 = 60 degrees. Since each interior and exterior angle pair up to make 180 degrees (a straight line), we can simply subtract that exterior angle from 180 to find θ, obtaining an angle of 180 - 60 = 120 degrees.
Finally, we substitute θ into our earlier formula to find that
6a = π(r^2)120/60
Or
6a = 2πr^2
So, the area of all six sectors is 2πr^2, or the area of two circles with radii r.
Simply
3Y+-21=12X
Re-order the terms
-21+3Y=12X
(Solving for Y variable)
Move all terms containing y to the left, all other terms to the right.
Add 21 to each side of the equation
-21+21+3Y=21+12X
Combine like terms: -21+21=0
0+3Y=21+12X
3Y=21+12X
Divide each side by 3
Y=7+4X
Simplifying
Y=7+4x
I hope this helps!! :)
