.015 is directly halfway between the two, so .013 is less than halfway
If the Amplitud is 11×2=22cm and the wave was in shm then we can get the wavelength as 11×2=22s.
From the wave equation,
v=fλ Where v⇒speed
f⇒frequency and
λ⇒Wavelength
And we know that;
f=1/T
f = 1/4 =0.25 Hz
∴v = 0.25 ×22 = 5.5 cm/s
Since we know know the speed of the object we can get its time it takes from (0-6.5) cm.
v = fλ = λ/T
∴T = λ/v
= 6.5/5.5
= 1 2/11
= 1.181818s
The time taken for the object <span>to move from x = 0.0 cm to x = 6.5 cm is </span>1.181818s
I hope this helps. I found the arc length by first,
getting the radius of 25 by dividing 50 in half. Then, multiplying 2π25 and 30 to get 4712.388. then you divide 4712.388 by 360 to get 13.089 as the answer.
Answer:
2x^3y−28
Step-by-step explanation:
If you need a step-by-step explanation please ask!
The answer has to be 1.25 I might be wrong tho
