646/3=x
To check it: x*3 should =646
Answer:
M=-1/3
Y=-1/3x + 4
The pictures too blurred, can you write it out?
Answer:
2.
A. (P+h)(x)
2x/x+4 (x-1) + x/x-1 (x+4)
2x^2-1/x^2-4
+
X^2+4/x^2-4
= 3x^2+3/x^2-4
B. (F-g)(x)
X^2-7x+6-x - 6
= x^2 -8x
C. (Fg)(x)
(X^2-7x+6)(x-6)
= x^3-13x^2+48x-36
D. (H/p)(x)
X/x-1 / 2x/x+4
X/x-1 / x+4/2x
= X^2+4x/2x^2-2x
3.
A. (F+g)(3)
X^2+1 + x-4
3^2+1 + 3-4
10 -1
= 9
B. (f-g)(0)
X^2+1 - x-4
0+1 -0-4
1-4
= -3
C. (Fg)(-k)
(X^2+1) (x-4)
(-k^2+1) (-k-4)
K^3+4k^2-k-4
D. (F/g)(k-2)
X^2+1 /x-4
K-2^2+1 / k-2 -2
= K^2-4k+5 / k-4
Step-by-step explanation:
Answer:
5a. 4w+24≤100
5b. Dimensions=31ft x 19 ft
Area = 589ft²
Step-by-step explanation:
l=w+12
p=2l+2w
p=2(w+12)+2w
p=2w+24+2w
p=4w+24
The farmer has 100ft of fencing, so maximum that the perimeter (p) can be is 100, meaning (4w+24) has to be less than or equal to 100:
4w+24≤100
For the largest possible perimeter, all 100 of fencing will be used, so allow 100 to be equal to 4w+24)
100=4w+24
4w=76
w=19ft
l=w+12
l=19+12
l=31ft
The dimensions are 31ft x 19ft.
Area=lw
=31*19
=589ft²
