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2 years ago

What is the effect on the graph of y=-2x+7 if the slope changes to 2

1 answer:

3 0

In y=-2x+7 the graph will rise from right to left while in y=2x+7 the graph will rise from left to right. Which gives us in conclusion of the slope is negative the graph line will rise from right to left and if positive then left to right

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Enter the equation of the line in slope-intercept form.

antiseptic1488 [7]

Answer:

ajfbgaulfgsuidglml

Step-by-step example:

4 0

3 years ago

Help me with my math quiz from friday 4/1 <br> SHOW STEPS

malfutka [58]

Hie!! I will be solving the questions in the sequence of the attachments.

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4. As line SU and TV are intersecting each other at O.

A.T.Q, ∠UOV = (7x - 4)°

∠SOT = 87°

Then, ∠UOV = ∠SOT {Vertically Opposite Angles}

$\rightarrow\sf{7x - 4=87}$

$\rightarrow\sf{7x =87+4}$

$\rightarrow\sf{7x =91}$

$\rightarrow\sf{x =\frac{91}{7}}$

$\rightarrow\boxed{\bf{x =13}}$

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5. radius = 17ft

circumference of circle = 2πr

$\rightarrow\sf{circumference=2\times\frac{22}{7}\times17}$

$\rightarrow\boxed{\bf{circumference=106.8ft}}$

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3. ∠1 and ∠2 - add to 180 (linear pair)

∠1 and ∠3 - equal (Vertically Opposite Angles)

∠3 and ∠4 - add to 180 (linear pair)

∠2 and ∠4 - equal (Vertically Opposite Angles)

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2. 160° + (6x - 16)° = 180° (linear pair)

$\rightarrow\sf{6x - 16 = 180-160}$

$\rightarrow\sf{6x - 16 = 20}$

$\rightarrow\sf{6x = 20+16}$

$\rightarrow\sf{6x =36}$

$\rightarrow\sf{x =\frac{36}{6}}$

$\rightarrow\boxed{\bf{x =6}}$

8 0

2 years ago

Choose the best coordinate system to find the volume of the portion of the solid sphere rho <_4 that lies between the cones φ

MrRissso [65]

Answer:

So, the volume is:

$\boxed{V=\frac{128\sqrt{2}\pi}{3}}$

Step-by-step explanation:

We get the limits of integration:

$R=\left\lbrace(\rho, \varphi, \theta):\, 0\leq \rho \leq 4,\, \frac{\pi}{4}\leq \varphi\leq \frac{3\pi}{4},\, 0\leq \theta \leq 2\pi\right\rbrace$

We use the spherical coordinates and we calculate a triple integral:

$V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}}\int_0^4 \rho^2 \sin \varphi \, d\rho\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \left[\frac{\rho^3}{3}\right]_0^4\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \cdot \frac{64}{3} \, d\varphi\, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} [-\cos \varphi]_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\$