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3 years ago

3a2 + 16a + 5 a2 – 7a + 10

Mathematics

1 answer:

schepotkina [342]3 years ago

6 0

This is thw answer:

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Answer:

$\lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1$ .

Step-by-step explanation:

We want to find $\lim_{x \to 2^-} \frac{|x-2|}{x-2}$ .

By definition:

$|x-2|=\left \{ {{x-2,\:if\:x\:>\:2} \atop {-(x-2),\:if\:x\:$

Since we want to find the Left Hand Limit, we use f(x)=-(x-2)

$\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} \frac{-(x-2)}{x-2}$ .

$\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} (-1)$ .

The limit of a constant is the constant.

$\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1$ .

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3 years ago

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Marizza181 [45]

Answer:

It is a line with a positive slope and positive intercept

Step-by-step explanation:

If you want it in SF, -x + y = 4

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X is not anything unless you show the equation with the variable

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