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VARVARA [1.3K]
3 years ago
13

3a2 + 16a + 5 a2 – 7a + 10

Mathematics
1 answer:
schepotkina [342]3 years ago
6 0
This is thw answer:


-

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WINSTONCH [101]
Hi um I think you posted a picture of something else other than the question!!
8 0
3 years ago
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Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
likoan [24]

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

5 0
3 years ago
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Find the equation of the line.<br><br>Use exact numbers.
Taya2010 [7]

Slope intercept form: y = mx + b

m = slope

b = y-intercept

The line passes through the y-axis at the point (0, -5). So, -5 is the y-intercept.

We can use the points (0, -5) and (5, 0) to solve.

Slope formula: y2-y2/x2-x1

0-(-5)/5-0)

5/5

1

The slope is 1.

Substitute these values into the equation.

y = 1x + (-5)

y = x - 5

Therefore, the answer is [ y = x - 5 ]

Best of Luck!

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3 years ago
How do i do it? Thank you for helping
castortr0y [4]

Answer:

a) 42. b) 64. c) 39.

Step-by-step explanation:

a. 6 x 7 = 42

b. 8 x 8 = 64

c. 3 x 13 = 39

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