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VARVARA [1.3K]
2 years ago
13

3a2 + 16a + 5 a2 – 7a + 10

Mathematics
1 answer:
schepotkina [342]2 years ago
6 0
This is thw answer:


-

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What is 8 - 4k = 40
olya-2409 [2.1K]
8-4k=40
-4k=32
k=-8 is the answer
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Solve this question fast....in the attachment​
avanturin [10]

Answer:

z = 4

y = -1

x = 2

Step-by-step explanation:

x - y = 3

Therefore => x = 3 + y

y + 2z =7

Therefore => y= 7 - 2z

We have the equation :

2x + 3y + 4z = 17

2(3 + y) + 3(7 - 2z) + 4z = 17

6 + 2y + 21 - 6z +4z = 17

2(7 -2z) - 2z + 27 = 17

14 - 4z - 2z + 27 = 17

-6z + 41 = 17

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2 years ago
Which value of a in the exponential function below would cause the function to stretch?
maxonik [38]

Answer:

“1.5”

Step-by-step explanation:

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2 years ago
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The owner of a fish market has an assistant who has determined that the weights of catfish are normally distributed, with mean o
Elis [28]
<span>mean of 3.2 pounds and standard deviation of 0.8 pound</span>
5 0
3 years ago
Find the maximum and minimum values of the function f(x,y)=2x2+3y2−4x−5 on the domain x2+y2≤100. The maximum value of f(x,y) is:
ryzh [129]

First find the critical points of <em>f</em> :

f(x,y)=2x^2+3y^2-4x-5=2(x-1)^2+3y^2-7

\dfrac{\partial f}{\partial x}=2(x-1)=0\implies x=1

\dfrac{\partial f}{\partial y}=6y=0\implies y=0

so the point (1, 0) is the only critical point, at which we have

f(1,0)=-7

Next check for critical points along the boundary, which can be found by converting to polar coordinates:

f(x,y)=f(10\cos t,10\sin t)=g(t)=295-40\cos t-100\cos^2t

Find the critical points of <em>g</em> :

\dfrac{\mathrm dg}{\mathrm dt}=40\sin t+200\sin t\cos t=40\sin t(1+5\cos t)=0

\implies\sin t=0\text{ OR }1+5\cos t=0

\implies t=n\pi\text{ OR }t=\cos^{-1}\left(-\dfrac15\right)+2n\pi\text{ OR }t=-\cos^{-1}\left(-\dfrac15\right)+2n\pi

where <em>n</em> is any integer. We get 4 critical points in the interval [0, 2π) at

t=0\implies f(10,0)=155

t=\cos^{-1}\left(-\dfrac15\right)\implies f(-2,4\sqrt6)=299

t=\pi\implies f(-10,0)=235

t=2\pi-\cos^{-1}\left(-\dfrac15\right)\implies f(-2,-4\sqrt6)=299

So <em>f</em> has a minimum of -7 and a maximum of 299.

4 0
3 years ago
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