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2 years ago

If the points plotted on a graph are scattfred randomly, what is the correlation?

Mathematics

1 answer:

kykrilka [37]2 years ago

8 0

Your answer here is D

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PLEASE HELP 20 POINTS!!!!!!!

svetoff [14.1K]

Answer:

18/25

Step-by-step explanation:

i dont have an explanation

3 0

2 years ago

10. What is the measure of angle C? A. 25° B. 30° C. 60° D. 75°

Reil [10]

Answer:

Step-by-step explanation:

x + 5 + 3x + C = 180 All triangles have 180 degrees.

4x + 5 + C = 180

But C must be equal to 3x. Notice the markings on the lets of the triangle.

4x + 5 + 3x = 180

7x + 5 = 180 Subtract 5 from both sides

7x = 180 - 5

7x = 175

x = 25

But angle C = 3x

C = 3*25

C = 75

8 0

3 years ago

How much money should be deposited today in an account that earns 4% compounded semi annually so that it will accumulate to 13,0

DedPeter [7]

Answer:

$11543.63

Step-by-step explanation:

Plug information into A=P(1+r/n)^nt

13000 = P(1+(.04/2))^(2*3)

13000 = P(1.02)^6

Isolate P

13000/(1.02^6) = P

P = $11543.63

5 0

2 years ago

You are planning a skating party at a rink that charges a basic fee of $6.00 and $6.50 per person for catered parties. You don’t

Alekssandra [29.7K]

Answer:

y = 6.50x + 6 or 71 = 6.50x + 6

10 people are the max you can invite

Step-by-step explanation:

We have the simple equation

y = 6.50x + 6

6.50x because it it per person

6 because it is a flat one time charge

We want the max to be 71 so that will be our y

71 = 6.50x + 6

We are now going to solve for x

65 = 6.5x

x = 10

Hope it helps! (:

4 0

2 years ago

Find the distance of the point (3,4) from the midpoint of the line joining (8,10) and (4,6)

Elis [28]

Answer:

Distance between point $(3,4)$ and midpoint of line joining $(8,10)$ and $(4,6)$ = $5$ units.

Step-by-step explanation:

Given:

Points:

$A(3,4)\\B(8,10)\\C(4,6)$

To find distance from point A to midpoint of BC.

Midpoint M of BC:

$M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\$

$M=(\frac{8+4}{2},\frac{10+6}{2})\\$ [Plugging in points $B(8,10)\ and\ C(4,6)$ ]

$M=(\frac{12}{2},\frac{16}{2})\\$

$M=(6,8)\\$

Distance between A and M:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\$

$D=\sqrt{(6-3)^2+(8-4)^2} \\$ [Plugging in points $A(3,4)\ and\ M(6,8)$ ]

$D=\sqrt{(3)^2+(4)^2} \\$

$D=\sqrt{9+16} \\$

$D=\sqrt{25} \\$

$D=\pm5$

Since distance is always positive ∴ $D= 5$ units

4 0

3 years ago