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myrzilka [38]
3 years ago
6

2) Mass of the earth is 5976000000000000000000000 kg and that of Uranus is 86800000000000000000000000 kg , which one has greater

mass ? and how much ? compare in exponential form.​
Mathematics
2 answers:
ad-work [718]3 years ago
8 0

Answer:

earrth has greater mass as it has higher density

koban [17]3 years ago
4 0

Step-by-step explanation:

mass of earth=5.976×10^24 and

mass of Uranus =8.68×10^25

the mass of

Uranus is greater than that of the Earth by comparing its power 10

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Hi!!!<br>Calcula los divisores de cada número :<br>8, 12 ,24 , 25 , 28, <br>please . _ .​
Kamila [148]
I think that it’s 23
6 0
3 years ago
The forumal below is used to convert a temputure in degrees celsius, C, to a tempurturein degrees fahrenheit, F.
Vika [28.1K]

Answer:

59 F

Step-by-step explanation:

F=1.8C+32

Let C = 15

F = 1.8 (15) +32

Multiply 1.8 times 15

F = 27+32

F = 59

15 degrees C is 59 degrees F

5 0
3 years ago
Jackson drinks 0.44 liters of water, which was 55% of the water in the bottle. How much water was in the bottle to start?
Delicious77 [7]

Answer:

He had 0.8 liters to start with...

Step-by-step explanation:

0.44 is 55% of what? (what = x)

Equation: Y = P% * X

X = Y/P%

X = 0.44/55%

55% = 0.55

X = 0.44/0.55

X = 0.8

7 0
4 years ago
Read 2 more answers
Find the GCF (greatest common factor) of 8 and 7.
FrozenT [24]

Answer: Its 1

Step-by-step explanation:

4 0
3 years ago
Polly's Polls asked 1850 second-year college students if they still had their original major. According to the colleges, 65% of
suter [353]

Answer:

The probability that Polly's Sample will give a result within 1% of the value 65% is 0.6424

Step-by-step explanation:

The variable that assigns the value 1 if a person had its original major and 0 otherwise is a Bernoulli variable with paramenter 0.65. Since she asked the question to 1850 people, then the number of students that will have their original major is a Binomial random variable with parameters n = 1850, p = 0.65.

Since the sample is large enough, we can use the Central Limit Theorem to approximate that random variable to a Normal random variable, which we will denote X.

The parameters of X are determined with the mean and standard deviation of the Binomal that we are approximating. The mean is np = 1850*0.65 = 1202.5, and the standard deviation is √np(1-p) = √(1202.5*0.35) = 20.5152.

We want to know the probability that X is between 0.64*1850 = 1184 and 0.66*1850 = 1221 (that is, the percentage is between 64 and 66). In order to calculate this, we standarize X so that we can work with a standard normal random variable W ≈ N(0,1). The standarization is obtained by substracting the mean from X and dividing the result by the standard deviation, in other words

W = \frac{X-\lambda}{\sigma} = \frac{X-1202.5}{20.5152}

The values of the cummulative function of the standard normal variable W, which we will denote \phi are tabulated and they can be found in the attached file.

Now, we are ready to compute the probability that X is between 1184 and 1221. Remember that, since the standard random variable is symmetric through 0, then \phi(-z) = 1-\phi(z) for each positive value z.

P(1184 < X < 1221) = P(\frac{1184-1202.5}{20.5152} < \frac{X-1202.5}{20.5152} < \frac{1221-1202.5}{20.5152})\\ = P(-0.9018 < W < 0.9018) = \phi(0.9018) - \phi(-0.9018) = \phi(0.9018)-(1-\phi(0.9018))\\ = 2\phi(0.9018)-1 = 2*0.8212-1 = 0.6424

Therefore, the probability that Polly's Sample will give a result within 1% of the value 65% is 0.6424.

Download pdf
4 0
3 years ago
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