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3 years ago

9

How do I identify the congruent triangles in each figure

1 answer:

Virty [35]3 years ago

5 0

Congruent triangles have the exact same three sides and the exact same angles. They are identical. So if you look at your triangles carefully, they are congruent. :)

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2 . .- no I M m ' ‘ n pm ‘ 3 v I \ v my . ’ v 3,-- . ‘ C . 9 was - v ., .. ‘ 1

Alina [70]

30 is the answer of this equation

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3 years ago

Priscilla invests $10,000 in an account that compounds interest continuously and earns 11%. How long will it take for her money

Shkiper50 [21]

Answer:

Step-by-step explanation:

When the interest compounds continuously, our formula is

$A(t)=Pe^{rt}$

If we start with 10000 and are looking for how long, t, it takes to double, we are looking for how long it will take for our account to have 2 times 10000. That's 20000. Therefore, our equation is

$20000=10000e^{.11t}$

Divide both sides by 10000 to get

$2=e^{.11t}$

Take the natural log of both sides to "undo" that e:

$ln(2)=ln(e^{.11t})$

Again, since ln and e undo each other what we have now is

ln(2) = .11t and

$\frac{ln(2)}{.11}=t$ so

t = 6.3 years

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2 years ago

Jo is thinking of a number. four less than 9 times the number is 176. find jo's number

luda_lava [24]

Answer:20

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

An entry code into a building is a 5-digit number.

lakkis [162]

Answer:B

Step-by-step explanation:

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3 years ago

The Weibull distribution is widely used in statistical problems relating to aging of solid insulating materials subjected to agi

fenix001 [56]

Answer:

Step-by-step explanation:

Given that

$\alpha =2.5$ , $\beta =220$

The weibull distribution with parameters $\alpha \ \ and \ \ \beta$

where $\alpha =0 \ \ , \beta =0$

$F(x,\alpha ,\beta) \left|\begin{array}{cc}\frac{\alpha }{\beta } x^{\alpha-1e^-(x/\beta)^\alpha &x\geq 0\\0&x$

Then,

$F(x,\alpha ,\beta )=\left|\begin{array}{cc}0&x$

A) The probability that a specimen's lifetime is at most 250 is

$P(X\leq 250)=F(250,2.7,220)\\\\=1-e^-^(250/220)^{2.7}\\\\=1-0.2436\\\\=0.7564$

The probability that the specimen's life time is more than 300 is

$P(X>300)=1-P(X\leq 300)\\\\=1-F(300;2.7,220)\\\\=1-(1-e^-^{(300/220)^{2.7}$

$=e^-^{(300/220)^{2.7}$

= 0.0992

b)The probability of the specimen's lifetime is between 100 and 250

$P(100$

c) The value such that exactly 50% of all specimens have lifetimes exceeding that value is

$P(X>x)=0.50\\\\1-P(X$

x = 192.07

7 0

3 years ago