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Reil [10]
3 years ago
5

I need help with this please !

Mathematics
2 answers:
S_A_V [24]3 years ago
8 0

Answer:

step 2 is wrong...-4-3=-7

Step-by-step explanation:

dimaraw [331]3 years ago
6 0

Answer:

1 or 2

Step-by-step explanation:

Both look wrong, but 1 seems worse. Sorry if this is wrong.

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A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n indepe
Finger [1]
The probability is 0.1458.

The probability is given by:

_{20}C_2(0.04)^2(1-0.04)^{20-2}
\\
\\=_{20}C_2(0.04)^2(0.96)^{18}=0.1458
5 0
3 years ago
Which step is the same in the construction of parallel lines and the construction of a perpendicular line through a point on the
madam [21]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

<em># Contracting parallel lines</em>

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2.<u> Place the pin of the compass at point C</u> and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

<em># Constructing a perpendicular line through a point on the line</em>

- Given line AB and point P lies on it

1. <u>Place your compass pin at P </u>and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3.<u> </u>Place the compass pin on point C<u> </u>and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

*<em> Lets find the same steps in the constructions</em>

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  <em><u>"Place the compass on a point on the original line"</u></em>

6 0
3 years ago
Read 2 more answers
(2x−12)+( 1 2 xy−10) (2x-12)+(12xy-10) for x=8 x=8 and y=2
Ratling [72]
(2(8)-12)+(12(8)(2)-10)
(16-12)+(132-10)
4+122=126
THE ANSWER WOULD BE 126 :D

5 0
4 years ago
Kim, Jenny, and Wendy are basketball players. Each plays a different position (guard, forward, and center) and wears a different
evablogger [386]
The answer is F because that is the only number left.
7 0
3 years ago
Read 2 more answers
Find the inverse of the function. Show work. <br> g(x)= - 3/x-2 +2
4vir4ik [10]

Answer:

\displaystyle g^{-1}(x)=\frac{-7+2x}{x-2}

Step-by-step explanation:

We are given the function:

\displaystyle g(x)=-\frac{3}{x-2}+2

Let's find the inverse of g.

Call y=g(x):

\displaystyle y=-\frac{3}{x-2}+2

We need to solve for x. Multiply both sides by x-2 to eliminate denominators:

y(x-2)=-3+2(x-2)

Operate:

yx-2y=-3+2x-4

Collect the x's to the left side and the rest to the right side of the equation:

yx-2x=-3-4+2y

Factor the left side and operate on the right side:

x(y-2)=-7+2y

Solve for x:

\displaystyle x=\frac{-7+2y}{y-2}

Interchange variables:

\displaystyle y=\frac{-7+2x}{x-2}

Call y as the inverse function:

\boxed{\displaystyle g^{-1}(x)=\frac{-7+2x}{x-2}}

5 0
3 years ago
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