Answer:
105
Step-by-step explanation:
15 times 7 =105
Answer:
x₂ = 7.9156
Step-by-step explanation:
Given the function ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ - f(xₙ)/f'(xₙ)
If f(x) = ln(x)+x-10
f'(x) = 1/x + 1
f(9) = ln9+9-10
f(9) = ln9- 1
f(9) = 2.1972 - 1
f(9) = 1.1972
f'(9) = 1/9 + 1
f'(9) = 10/9
f'(9) = 1.1111
x₁ = x₀ - f(x₀)/f'(x₀)
x₁ = 9 - 1.1972/1.1111
x₁ = 9 - 1.0775
x₁ = 7.9225
x₂ = x₁ - f(x₁)/f'(x₁)
x₂ = 7.9225 - f(7.9225)/f'(7.9225)
f(7.9225) = ln7.9225 + 7.9225 -10
f(7.9225) = 2.0697 + 7.9225 -10
f(7.9225) = 0.0078
f'(7.9225) = 1/7.9225 + 1
f'(7.9225) = 0.1262+1
f'(7.9225) = 1.1262
x₂ = 7.9225 - 0.0078/1.1262
x₂ = 7.9225 - 0.006926
x₂ = 7.9156
<em>Hence the approximate value of x₂ is 7.9156</em>
Total impedance of circuit is Z1 + Z2
Here it is important that real numbers we sum with real numbers and complex numbers with complex numbers
Let Zs represent total impedance.
Zs = Z1 + Z2 = 3 + 4i + 5 - 2i = 3 + 5 + 4i - 2i = 8 + 2i
Answer is :
8+2i
Answer:
$3100
Step-by-step explanation:
Step one:
given data
Principal = $2500
rate = 1.2%
time = 20 years
Step two:
The simple interest is expressed as
SI= PRT/100
substitute
SI= 2500*1.2*20/100
SI= $600
The account balance after 20 years is
= principal + Simple interest
= 2500+600
= $3100
Answer:
ok
Step-by-step explanation:
