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2 years ago

...............................................................So help.

Mathematics

2 answers:

dusya [7]2 years ago

5 0

23. 3/11 as a decimal is 0.27272727.

24. 5/8 as a decimal is 0.625.

25. 7/10 as a decimal is 0.7.

26. 2 5/7 as a decimal is 2.71428571.

And lastly, 27. -1 80/99 as a decimal is 1.888888.

<em>If something seems incorrect here, please don't refrain to tell me.</em>

makkiz [27]2 years ago

3 0

Answer: 3/11 = 0.27272727272727, -5/8 = 0.625

Step-by-step explanation:

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Step-by-step explanation:

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Replace m with 46x10^4 in the equation and solve.

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2 years ago

Multiple Response: Please select all correct answers and click "submit." Which of the following are among the five basic postula

Kazeer [188]

To Euclid, a postulate is something that is so obvious it may be accepted without proof.

A. A straightedge and compass can be used to create any figure.

That's not Euclid, that's just goofy.

B. A straight line segment can be drawn between any two points.

That's Euclid's first postulate.

C. Any straight line segment can be extended indefinitely.

That's Euclid's second postulate.

D. The angles of a triangle always add up to 180.

That's true, but a theorem not a postulate. Euclid and the Greeks didn't really use degree angle measurements like we do. They didn't really trust them, I think justifiably. Euclid called 180 degrees "two right angles."

Answer: B C

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3 years ago

What is the location of D on the decimal number line

natta225 [31]

Answer:

need more information ?

Step-by-step explanation:

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3 years ago

Suppose a simple random sample of size n is drawn from a large population with mean mu and standard deviation sigma. The samplin

Sidana [21]

Answer:

$X \sim N(\mu,\sigma)$

Where $\mu$ the mean and $\sigma$ the deviation

Since the distribution for X is normal then we can conclude that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = \mu$

$\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,\sigma)$

Where $\mu$ the mean and $\sigma$ the deviation

Since the distribution for X is normal then we can conclude that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = \mu$

$\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}$

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2 years ago

Read 2 more answers