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3 years ago

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Given: △AKM, KD ⊥ AM , AK = 6, KM = 10, m∠AKM = 93º Find: KD

2 answers:

NNADVOKAT [17]3 years ago

8 0

<em><u>Answer:</u></em>

<h3>⇒KD=5.0262 </h3><h3>⇒KD≈5</h3>

<u>Explanation</u>:

<h3>⇒Given in attached figure</h3>

Vesna [10]3 years ago

4 0

Do you have a photo where I can see your problem?

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3 years ago

5. Mis the midpoint of CD. C has coordinates (-1,-1) and

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Thus:

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5. Given M(3, 5) as midpoint of CD, and C(-1, -1),

let $C(-1, -1) = (x_2, y_2)$

$D(?, ?) = (x_1, y_1)$

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Rewrite the equation to find the coordinates of D

$3 = \frac{x_1 - 1}{2}$ and $5 = \frac{y_1 - 1}{2}$

Solve for each:

$3 = \frac{x_1 - 1}{2}$

$3*2 = \frac{x_1 - 1}{2}*2$

$6 = x_1 - 1$

$6 + 1= x_1 - 1 + 1$

$7 = x_1$

$x_1 = 7$

$5 = \frac{y_1 - 1}{2}$

$5*2 = \frac{y_1 - 1}{2}*2$

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$11 = y_1$

$y_1 = 11$

Coordinates of D is (7, 11)

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3 years ago