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Studentka2010 [4]
3 years ago
15

Consider the following system of equations. StartLayout Enlarged left-brace 1st row negative 10 x squared minus 10 y squared = n

egative 300 2nd row 5 x squared + 5 y squared = 150 EndLayout
Mathematics
2 answers:
lubasha [3.4K]3 years ago
5 0

Answer:

answer is D :)

Step-by-step explanation:

ziro4ka [17]3 years ago
4 0

These 2 equations has no solution and the equations are independent of each other.

<u>Step-by-step explanation:</u>

-10x² -10y² = -300 ----a

5x² + 5y² = 150 ---- b

While trying to solve this,

We can multiply the eq. b by 2 so we will get eq. c and then add to eq. a we will get 0 as the solution.

10x² + 10y² = 300 ----c

-10x² -10y² = -300 ---a

Everything cutoff, we will get 0, and there is no solution to these equations.

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Step-by-step explanation:

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2 years ago
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3 0
3 years ago
Question number 1: 5/8 (16b+24) -1/2b<br><br> Question number 2: 3/4 (16/64 + 12a) -9a
Sophie [7]

Answer:

Problem 1. <em>(19/2)b + 15</em>

Problem 2. <em>3/16</em>

Step-by-step explanation:

Question number 1

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Question number 2

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= (3 * 16)(4 * 64) + (3/4) * (12/1) * a - 9a

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5 0
3 years ago
I have a math question it is... what is g - 3/7 = 2/7 ?
stira [4]

 

g - 3/7 = 2/7   is an equation.


\displaystyle\bf\\g-\frac{3}{7}=\frac{2}{7}\\ \\g=\frac{2}{7}+\frac{3}{7}=\frac{2+3}{7}=\frac{5}{7}\\\\\boxed{\bf g=\frac{5}{7}}





6 0
2 years ago
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