Question

Consider the following system of equations. StartLayout Enlarged left-brace 1st row negative 10 x squared minus 10 y squared = negative 300 2nd row 5 x squared + 5 y squared = 150 EndLayout

Answer 1

Answer:

answer is D :)

Step-by-step explanation:

Answer 2

These 2 equations has no solution and the equations are independent of each other.

Step-by-step explanation:

-10x² -10y² = -300 ----a

5x² + 5y² = 150 ---- b

While trying to solve this,

We can multiply the eq. b by 2 so we will get eq. c and then add to eq. a we will get 0 as the solution.

10x² + 10y² = 300 ----c

-10x² -10y² = -300 ---a

Everything cutoff, we will get 0, and there is no solution to these equations.