Check the picture below.
so the area of the hexagon is really just the area of two isosceles trapezoids.
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ a=2\\ b=4\\ h=2 \end{cases}\implies \begin{array}{llll} A=\cfrac{2(2+4)}{2}\implies A=6 \\\\\\ \stackrel{\textit{twice that much}}{2A = 12} \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D2%5C%5C%20b%3D4%5C%5C%20h%3D2%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20A%3D%5Ccfrac%7B2%282%2B4%29%7D%7B2%7D%5Cimplies%20A%3D6%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwice%20that%20much%7D%7D%7B2A%20%3D%2012%7D%20%5Cend%7Barray%7D)
17.05 I think..
this could be it idrk what it is
Step-by-step explanation:
and,
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☆Find the 
Here,
BC =AC
so,
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we know that,
But 
(Ģìvéñ)
so..
But...
soo,
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Answer:
No, Angela is not correct.
As the method Jim was performing will also lead to the solution.
Step-by-step explanation:
We are given first equation as:
Ax + By = C
Second equation is:
Dx + Ey = F
Jim solved the equation as:
He begins by multiplying equation (1) by D and equation (2) by A.
and so by subtracting both the equations he will obtain a value of y.
and then put the y-value in any of the given two equations to obtain the value of x.
Angela Method:
you should have multiplied equation (1) by E and equation (2) by B.
and when she will subtract both the equations she will get the value of x first and then when she will put the value of x in any of the given equation she will obtain the value of y.
But both will get a value for x and y.
Hence, the method Jim was performing was also correct.
Answer: There are 12 months in one 1 year
Step-by-step explanation:
