Let O be the center of a circle. If <span>the measure of arc RS is 84 degrees, then m∠SOR=84^{0}. The triangle SOR is isoscales (because SO=OR as radii), so m∠RSO=m∠ORS=(180^{0}-84^{0}):2=48^{0}.
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Line RU is tangent to the circle in point R, this means that m∠ORU=90^{0}.
Consider the triangle SRU. m∠RSU=30^{0} and m∠SRU=48^{0}+90^{0}=138^{0}, then m∠RUS=180^{0}-30^{0}-138^{0}=12^{0}.
ANSWER: Correct choice B - 12^{0}.
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Answer:
viu'bk
Step-by-step explanation:
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The first choice.
The equation of this first line is -2, and since there is an open circle, it is not equal to -3.
The equation of the second line is -x-2, and there is a closed circle, so it includes -3
1) 0.927184
2) 0.615661
3) 0.383864
