Answer:
The probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.
Step-by-step explanation:
Let the random variable <em>X</em> represent the miles-per-gallon rating of passenger cars.
It is provided that 
.
Compute the probability that a randomly selected passenger car gets more than 37.3 mpg as follows:
Thus, the probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.
Answer:
Step-by-step explanation:
<em>Refer to attached</em>
<u>Comparing sales by the ratio of sold to all or</u>
- Sales = sold / (remaining + sold)
<u>Applying to our table:</u>
- New Labels: p/(p+q)
- Old labels: r/(r+s)
Correct answer option is the last one
Answer:
6+y 
-23
Step-by-step explanation:
Just write it out.
Answer:
<h2>
d = 245</h2>
Step-by-step explanation:
d is directly proportional to the square of a speed v
d = av²
5 = a•10²
5 = 100a
a = 0.05
d = 0.05v²
d = 0.05•70²
d = 0.05•4900
d = 245
