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Yuki888 [10]
3 years ago
12

The figure below is a rhombus. z = [?]

Mathematics
1 answer:
Nonamiya [84]3 years ago
3 0

Answer:

28 degrees

Step-by-step explanation:

z and x are the same. Do the math.

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A circle has a radius of 8 centimeters. The measure of the arc of the
Gnesinka [82]

Answer: 10.1

Step-by-step explanation:

3 0
3 years ago
IA triangular parking lot is paved outside a new shopping center. The lengths of the sides of the parking lot are 100 meters, 11
Gemiola [76]

Answer:

Step-by-step explanation:

I believe the only way to solve this is by Heron's Formula.

Add up all the sides and divide by 2 to get the semi-perimeter:

113+100+86 = 299

299/2 = 149.5

Now fill in the rest, which looks like this:

\sqrt{s(s-a)(s-b)(s-c)}

where s is your semiperimeter value, a is the length of one side, b the length of another side, and c the length of the third side:

\sqrt{149.5(149.5-113)(149.5-100)(149.5-86)}

which simplifies to

\sqrt{149.5(36.5)(49.5)(63.5)}

which simplifies further to

\sqrt{17151929.44}

which, on your calculator, is 4141.49 meters squared (that's rounded to the nearest hundredth).

4 0
3 years ago
Thanks to all those who support my question!
Mazyrski [523]

Answer:

no, because intergers are negative. they will never be able to be greater

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A chair’s regular price is $349. It is on clearance for 30% off, and a customer uses a
Hunter-Best [27]

Answer:

$207.66

Step-by-step explanation:

349x.7=244.3

244.3x.85=207.665

Rounded to the nearest 100th

207.66

7 0
3 years ago
Read 2 more answers
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
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