Help plz asap the question in the picture

According to the study unit, the subtrahend is defined as A. the number being subtracted. B. the name of the subtraction symbol.

yan [13]

its A /:)

the number being subtracted

5 0

3 years ago

Read 2 more answers

a spherical balloon is being inflated so that the radius is increasing at a rate of 3 cm/sec. find the rate at which the volume

neonofarm [45]

Answer: 1200pi cubic cm per sec

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Work Shown:

dr/dt = 3 is the rate of change of the radius

V = (4/3)pi*r^3 ..... volume of a sphere

dV/dt = (4/3)*3*pi*r^2*dr/dt ... chain rule

dV/dt = 4*pi*r^2*dr/dt

dV/dt = 4*pi*r^2*3

dV/dt = 12*pi*r^2

dV/dt = 12*pi*10^2 ... plug in r = 10

dV/dt = 1200pi

3 0

3 years ago

a man made lake is stocked with 10,000 fish. This population is expected to decline by an annual rate of 15%. Predict the fish p

Rasek [7]

I got 2,500 left after 5 years.
10,000*15% = 1,500 or you could do 10,000*.15 = 1,500

That is a loss of 1,500 fish per year.
If you want to think of this as a proportion then you would do
Year/fish lost

1/1,500 = 5/x
X=5*1,500
X=7,500

The population of the fish after 5 years equals
10,000-7,500 = 2,500
So your answer is 2,500 fish are left

8 0

3 years ago

Can anyone help me with this one :D

allsm [11]

Answer:

the answers is (10^1)^3 = 1000

4 0

3 years ago

Use the unit circle to evaluate these expressions:

sergeinik [125]

Answer:

a) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4$

For this case we know that $sin (\pi/4) = \frac{\sqrt{2}}{2}$

So then $sin(\frac{17 \pi}{4}) = \frac{\sqrt{2}}{2}$

b) We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$19 \pi/6 - 2\pi = \frac{7\pi}{6}$

For this case we know that $cos (\pi/6) = \frac{\sqrt{3}}{2}$

And we know that $\frac{7\pi}{6}$ is on the III quadrant since is equivalent to 210 degrees. And on the III quadrant the cosine is negative. So then $cos(\frac{19 \pi}{6}) = -\frac{\sqrt{3}}{2}$

c) For this case that any factor of $\pi$ the sin function is equal to 0.

So from definition of tan we have this:

$tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0$

Step-by-step explanation:

a. sin (17pi / 4 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$17 \pi/4 - 2\pi = \frac{9\pi}{4} -2\pi = \pi/4$

For this case we know that $sin (\pi/4) = \frac{\sqrt{2}}{2}$

So then $sin(\frac{17 \pi}{4}) = \frac{\sqrt{2}}{2}$

b. cos (19pi / 6 )

We can remove the complete rotations around the unitary circle like this, because we know that one complete revolution is equivalent to $2\pi$ :

$19 \pi/6 - 2\pi = \frac{7\pi}{6}$

For this case we know that $cos (\pi/6) = \frac{\sqrt{3}}{2}$

And we know that $\frac{7\pi}{6}$ is on the III quadrant since is equivalent to 210 degrees. And on the III quadrant the cosine is negative. So then $cos(\frac{19 \pi}{6}) = -\frac{\sqrt{3}}{2}$

c. tan(450pi)

For this case that any factor of $\pi$ the sin function is equal to 0.

So from definition of tan we have this:

$tan (450\pi) = \frac{sin(450 \pi)}{cos(450 \pi)}= \frac{0}{cos(450\pi)}= 0$

4 0

3 years ago