I thing the answer is 7 days
The vertex U' is located at (-4, -5)
<h3>How to determine the location of U'?</h3>
The vertices are given as:
U = (-4, 5)
V = (-6, 2)
The rule of transformation is given as:
Reflection across the x-axis
This is represented as:
(x, y) => (x, -y)
So, we have:
U' = (-4, -5)
Hence, the vertex U' is located at (-4, -5)
Read more about transformation at:
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<u>Complete question</u>
Quadrilateral UVWX is reflected over the x-axis to form quadrilateral U′V′W′X′. If vertex U is located at (-4, 5) and vertex V is located at (-6, 2), then vertex U′ is located at
√7x-49<span>√x Tell if you need to see the work
</span>
The x =0 and y = 1 are coordinates of point E, which partitions the directed line segment from A to B into a ratio of 1:2.
<h2>We have to determine</h2>
What are the x- and y- coordinates of point E, which partitions the directed line segment from A to B into a ratio of 1:2?
<h3>According to the question</h3>
A line segment at points A(2, -3) and B (-4, 9).
The x- and y- coordinates of point E, which partitions the directed line segment from A to B into a ratio of 1:2 is given by;
![\rm x=\dfrac{m}{(m+n)} [x_2- x_1]+ x_1 \\ \\ y=\dfrac{m}{(m+n)} [y_2- y_1]+ y_1 \\ \\](https://tex.z-dn.net/?f=%5Crm%20x%3D%5Cdfrac%7Bm%7D%7B%28m%2Bn%29%7D%20%5Bx_2-%20x_1%5D%2B%20x_1%20%5C%5C%0A%5C%5C%0A%20y%3D%5Cdfrac%7Bm%7D%7B%28m%2Bn%29%7D%20%5By_2-%20y_1%5D%2B%20y_1%20%5C%5C%0A%5C%5C)
Where 
Substitute all the values in the formula;
![\rm x=\dfrac{m}{(m+n)} [x_2- x_1]+ x_1 \\\\](https://tex.z-dn.net/?f=%5Crm%20x%3D%5Cdfrac%7Bm%7D%7B%28m%2Bn%29%7D%20%5Bx_2-%20x_1%5D%2B%20x_1%20%5C%5C%5C%5C%20)
![\rm x=\dfrac{1}{(1+2)} [-4-(2)]+ (2)\\\\ x = \dfrac{1}{3} \times (-6) +2 \\ \\ x = -2+2\\ \\ x=0](https://tex.z-dn.net/?f=%5Crm%20x%3D%5Cdfrac%7B1%7D%7B%281%2B2%29%7D%20%5B-4-%282%29%5D%2B%20%282%29%5C%5C%5C%5C%20x%20%3D%20%5Cdfrac%7B1%7D%7B3%7D%20%5Ctimes%20%28-6%29%20%2B2%20%5C%5C%0A%5C%5C%0Ax%20%3D%20-2%2B2%5C%5C%0A%5C%5C%0Ax%3D0)
![\rm y=\dfrac{m}{(m+n)} [y_2- y_1]+ y_1 \\\\ y=\dfrac{1}{(1+2)} [9-(-3)]+ (-3)\\\\ y = \dfrac{1}{3} \times (12) -3\\ \\ y = 4-3\\ \\ y =1](https://tex.z-dn.net/?f=%5Crm%20y%3D%5Cdfrac%7Bm%7D%7B%28m%2Bn%29%7D%20%5By_2-%20y_1%5D%2B%20y_1%20%5C%5C%5C%5C%20y%3D%5Cdfrac%7B1%7D%7B%281%2B2%29%7D%20%5B9-%28-3%29%5D%2B%20%28-3%29%5C%5C%5C%5C%0Ay%20%3D%20%5Cdfrac%7B1%7D%7B3%7D%20%5Ctimes%20%2812%29%20-3%5C%5C%0A%5C%5C%0Ay%20%3D%204-3%5C%5C%0A%5C%5C%0Ay%20%3D1)
Hence, the x =0 and y = 1 are coordinates of point E, which partitions the directed line segment from A to B into a ratio of 1:2.
To know more about Coordinates click the link given below.
brainly.com/question/13847533