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3 years ago

Two different types of candy cost 2x, 7x. If you buy 2 of each type, write down an algebric expression of the total cost

Mathematics

1 answer:

deff fn [24]3 years ago

5 0

Answer:

$(18x)

Step-by-step explanation:

2(2x)+2(7x)

=4x+14x

=18x

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How do you expand (5x+ 1)(5x-1)

AnnyKZ [126]

Step-by-step explanation:

Multiply both numbers so

25x2 - 6x + 6x - 1

25x2 - 1

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A rectangle has a length of 9.00 inches and a width of 4.25 inches. What is the area in square inches? Round to the correct sign

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9 times 4.25 = 38.25 inches area of a rectangle is length times width

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A grasshopper jumps from the ground. The path of the grasshopper is modeled by the equation y=−0.5x2+8x where x is the horizonta

Marysya12 [62]

Please use " ^ " to indicate exponentiation: <span>y=−0.5x^2+8x

Examining this function, we see that its graph is a vertical parabola opening down.

You did not supply instructions for this problem.
However, one could guess that you might want to find the highest point of the grasshopper's path. To do this, find the vertex: Find the x value defined by

x = -b/(2a). Here, a= -0.5 and b= 8. Thus, the vertex is at x = -8/(2[-0.5]), or

x -8/(-1) = 8 units. The corresponding y value is then

y = </span><span>−0.5*8^2+8(8) = -0.5(64) + 64, or 32 units.</span>

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2 years ago

Guess a number between 1-3 whoever gets it gets brainliest

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I guess the number 3

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The diagram shows a 5 cm x 5 cm x 5 cm cube.

mylen [45]

Answer:

~8.66cm

Step-by-step explanation:

The length of a diagonal of a rectangular of sides a and b is

$\sqrt{a^2+b^2}$

in a cube, we can start by computing the diagonal of a rectangular side/wall containing A and then the diagonal of the rectangle formed by that diagonal and the edge leading to A. If the cube has sides a, b and c, we infer that the length is:

$\sqrt{\sqrt{a^2+b^2}^2 + c^2} = \sqrt{a^2+b^2+c^2}$

Using this reasoning, we can prove that in a n-dimensional space, the length of the longest diagonal of a hypercube of edge lengths $a_1, a_2, a_3, \ldots, a_n$ is

$\sqrt{a_1^2 + a_2^2 + a_3^2 + \ldots + a_n^2}$

So the solution here is

$\sqrt{(5cm)^2 + (5cm)^2 + (5cm)^2} = \sqrt{75cm^2} = 5\sqrt{3cm^2} \approx 5\cdot 1.732cm = 8.66cm$

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