The distance between (3, 1) and (6, 5) is 5.
D=√(x₂-x₁)²+(y₂-y₁)²
D=√(6-3)²+(5-1)²
D=√3²+4²
D=√9+16
D=√25
D=5
To eliminate the fraction, we multiply by 4
<h3>How to eliminate the fractions?</h3>
The equation is given as:
-3/4m-1/2=2+1/4m
Rewrite properly as:

The denominators of the above fractions are 2 and 4
The LCM of 2 and 4 is 4
So, we multiply through by 4.
This gives
-3m - 2 = 8 + m
Hence, to eliminate the fraction, we multiply by 4
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Answer:
The third side must be smaller than 20 inches and greater than 4 inches

Step-by-step explanation:
Let a, b and c be the lengths of triangle's sides. Then

Use this rule in your case. So, if a=12 and b=8, then

Hence, you get

From these inequalities, you can state that

So, c must be smaller than 20 inches and greater than 4 inches.