First you'd substitute x= y-3 in the first equation.
10(y-3) -10y= 1
10y - 30 -10y= 1
The y's cancel each other out, so you're left with -30= 1. That means there's no solution :)
Answer:
Yes
Step-by-step explanation:
The sum must be greater than 8 it can't be 7 anyway. Sums can be 9, 10 or 12. P = (4+3+1)/36 = 3/36
