B is the midpoint of AC, AB = 3x - 8 and BC = x + 4. Find AB

1 answer:

8 0

Since b is the midpoint BC is half the line so we can set up this equation

x+4+X+4=3x-8

and then solve like normal

2x+8=3x-8

16=x

once you have x then solve x+4

16 + 4 =20

AB is 20

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(6x-2y-5)-(-5+9y-8x)

pav-90 [236]

Answer:

14x-11y

Step-by-step explanation:

6x-2y-5=5-9y+8x

eliminate opposites

6x-2y-9y+8x

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14x-11y

7 0

4 years ago

Two lighthouses are located 60 miles from one another on a north-south line. If a boat is spotted S 21o E from the northern ligh

jasenka [17]

Answer:

(A)The northern lighthouse is 8.2 miles closer than the southern lighthouse.

Step-by-step explanation:

The triangle attached represents the given problem.

First, let us determine the distance of the Boat from each of the lighthouse.

In Triangle ABC,

∠A+∠B+∠C=180 degrees

21+∠B+16=180

∠B=180-37=143 degrees.

Using Law of Sines

$\frac{a}{Sin A}=\frac{b}{Sin B}\\\frac{a}{Sin 21^0}=\frac{60}{Sin 143^0} \\\text{Cross Multiply}\\a*sin143=60*sin21\\a=60*sin21\div sin143\\a=35.73 miles$

Similarly

$\frac{c}{Sin C}=\frac{b}{Sin B}\\\frac{c}{Sin 16^0}=\frac{60}{Sin 143^0} \\\text{Cross Multiply}\\c*sin143=60*sin16\\c=60*sin16\div sin143\\c=27.48 miles$