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Aleonysh [2.5K]
3 years ago
7

Why are all of the substances on the periodic table classified as elements?

Chemistry
2 answers:
Amanda [17]3 years ago
5 0

Substances on the periodic table cannot be broken down into other substances and are therefore elements. I just took the test and this is correct.

Readme [11.4K]3 years ago
4 0

All elements are pure substances.

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What do dinking objects have in common
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They all have densities greater than the density of the fluid in which they are<span>sinking. The mass of the displaced liquid is less than the mass of the sinking body.</span>
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4 years ago
Draw the structure of 1,4-hexanediamine.
brilliants [131]

Answer:

1,4-hexanediamine contains two -NH_{2} functional groups.

Explanation:

1,4-hexanediamine is an organic molecule which contains two -NH_{2} functional groups at C-1 and C-4 position.

The longest carbon chain in 1,4-hexanediamine contains six carbon atoms.

Molecular formula of 1,4-hexanediamine is C_{6}H_{16}N_{2}.

1,4-hexanediamine used as a bidentate ligand in organometallic chemistry.

The structure of 1,4-hexanediamine is shown below.

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3 years ago
Which statement best describes the model that shows a compound?
VashaNatasha [74]
B is the.answer for this problem
5 0
3 years ago
Read 2 more answers
Identify the statement that accurately describes ATP
Grace [21]

Answer:

Adenosine triphosphate

In science, ATP stands for adenosine triphosphate. This chemical, discovered in the 1920s, is important to all life. It stores and releases energy for many cellular processes. It is found in mitochondria.

Explanation:

3 0
3 years ago
When 125.0 g of ethylene (C2H4) burns in 60.0 grams of oxygen to give carbon dioxide and water, how many grams of CO2 are formed
gizmo_the_mogwai [7]

Answer:

             66 g of CO₂

Solution:

The Balance Chemical Reaction is as follow,

                             C₂H₂  +  5/2 O₂    →    2 CO₂  +  H₂O

Or,

                             2 C₂H₂  +  5 O₂    →    4 CO₂  +  2 H₂O    -------  (1)

Step 1: Find out the limiting reagent as;

According to Equation 1,

            56.1 g (2 mole) C₂H₂ reacts with  =  160 g (5 moles) of O₂

So,

                  125 g of C₂H₂ will react with  =  X g of O₂

Solving for X,

                      X =  (125 g × 160 g) ÷ 56.1 g

                      X =  356.5 g of O₂

It means for total combustion of Ethylene we require 356.5 g of O₂, but we are only provided with 60.0 g of O₂. Therefore, O₂ is the limiting reagent and will control the yield.

Step 2: Calculate Amount of CO₂ produced as;

According to Equation 1,

              160 g (5 mole) O₂ produces  =  176 g (4 moles) of CO₂

So,

                  60.0 g of O₂ will produce  =  X g of CO₂

Solving for X,

                      X =  (60.0 g × 176 g) ÷ 160 g

                      X =  66 g of CO₂

8 0
3 years ago
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