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Elanso [62]
3 years ago
13

A 1.50-liter sample of dry air in a cylinder exerts a pressure of 3.00 atmospheres at a temperature of 25°C. Without changing th

e temperature, a piston is moved in the cylinder until the pressure in the cylinder is reduced to 1.00 atmospheres. The volume of the gas is _____.
Chemistry
1 answer:
nikitadnepr [17]3 years ago
8 0

Answer:

4.50 liters

Explanation:

Boyles law P1 · V1 =P2 · v2

V2=P1·V1÷P2

V2= 3 · 1.5 ÷ 1

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This cold river of air travels from west to east in the northern hemisphere. In winter, it dips south helping to bring cooler ai
Alex_Xolod [135]

Answer:

Polar Jet stream

Explanation:

Polar Jet stream is also called the polar front jet or mid latitude jet steam, it is a very powerful belt of the upper level winds which sits above the polar front. It is the strongest wind in the tropopause, it's movement is towards the westerly direction of the mid latitude.

4 0
3 years ago
First-order reaction that results in the destruction of a pollutant has a rate constant of 0.l/day. (a) how many days will it ta
Klio2033 [76]

Rate equation for first order reaction is as follows:

t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}

Here, k is rate constant of the reaction, t is time of the reaction, A_{0} is initial concentration and A_{t} is concentration at time t.

The rate constant of the reaction is 0.1 day^{-1}.

(a) Let the initial concentration be 100, If 90% of the chemical is destroyed, the chemical present at time t will be 100-90=10, on putting the values,

t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{10}=23.03 days

Thus, time required to destroy 90% of the chemical is 23.03 days.

(b) Let the initial concentration be 100, If 99% of the chemical is destroyed, the chemical present at time t will be 100-99=1, on putting the values,

t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{1}=46.06 days

Thus, time required to destroy 99% of the chemical is 46.06 days.

(c)  Let the initial concentration be 100, If 99.9% of the chemical is destroyed, the chemical present at time t will be 100-99.9=0.1, on putting the values,

t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{0.1}=69.09 days

Thus, time required to destroy 99.9% of the chemical is 69.09 days.

5 0
3 years ago
I need help with this ASAP.
adelina 88 [10]

Answer:

bob

Explanation:

owa owa owa

3 0
3 years ago
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omeli [17]
64 divided by 4 is 16, so 16 km every 15 minutes.
15 x 3 is 45, so the distance is 16 x 3, and 16 x 3 equals 48.
It has traveled 48 km after traveling for 45 minutes. Hope this helped :)
8 0
3 years ago
Of these four liquids which is the most viscous?<br> a) h20<br> b) ccl4<br> c) c2h12o6<br> d) Hg
Tresset [83]
Answer is: d) Hg.
Mercury is a chemical element with the symbol Hg and atomic number 80. <span> Mercury is the only metallic element that is liquid at standard conditions for temperature and pressure.
</span>Absolute viscosity of mercury is 0,0015 Pa·s.
The viscosity<span> of a </span>fluid<span> is a measure of its </span>resistance<span> to gradual deformation by </span>shear stress<span> or </span><span>tensile stress</span>

7 0
3 years ago
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