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Kazeer [188]
4 years ago
7

What do dinking objects have in common

Chemistry
1 answer:
Viefleur [7K]4 years ago
5 0
They all have densities greater than the density of the fluid in which they are<span>sinking. The mass of the displaced liquid is less than the mass of the sinking body.</span>
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How many grams are in 5.00 * 10^25 atoms of helium
statuscvo [17]

Answer:

dfghgvfdsrftgbnbvcdfvgbhnbvcxsdefrgthbvcxdsfgt

Explanation:

sdfgvfcdsertgyhbvcfxdsrftgh

4 0
3 years ago
The
Vikki [24]

2nd

Explanation:

because i guesses i guess so yeah trust your gut buddy

5 0
3 years ago
Calculate the pH of 500cm3 of 0.2mol/dm3 Ca(OH2), assume complete ionisation​
Lilit [14]

Answer:

The pH of 500 cm³, 0.2 mol/dm³, Ca(OH₂) is ≈ 13.6

Explanation:

The given parameters are;

Concentration of the calcium hydroxide, Ca(OH₂) = 0.2 mol/dm³

Volume of the calcium hydroxide, Ca(OH₂) = 500 cm³

Given that the calcium hydroxide, Ca(OH₂),  undergoes complete ionization in water, complete dissociation, we have;

Ca(OH₂)  ⇄  Ca²⁺ + 2 OH⁻

Therefore, we have;

2 moles of [OH⁻] for each mole of Ca(OH₂) which gives the concentration of  [OH⁻] as

[OH⁻] = 2 × 0.2 ≈ 0.4 mol/dm³

The pH is given by the formula

pH = 14 + ㏒₁₀ [OH⁻]

pH = 14 + ㏒₁₀ (0.4) = 14 - 0.3979 = 13.6021 ≈ 13.6

The pH of the 500 cm³ 0.2 mol/dm³ Ca(OH₂) ≈ 13.6.

4 0
3 years ago
Why do we apply paint on an articles​
Alex Ar [27]

Answer:

Answer: ... When iron is exposed to the environmental condition it terribly reacts with water and air and ends up with iron rusting. Iron articles are therefore painted off so that iron can not react with water and air.

I hope this will help you...

5 0
4 years ago
How many asymmetric centers are present in the open chain form of the aldohexose D-(-)-gulose?
bulgar [2K]

Answer:

D) 4

Explanation:

If we want to find the asymmetric centers, we must first remember that in an asymmetric center, in the carbon, we will have 4 different types of groups bonded to it.

Therefore we must look for carbons that have 4 different groups. With this in mind, we can look at each carbon.

<u>Carbon 1</u>

In this carbon, we have two bonds with the oxygen, therefore, we dont have 4 different groups. So, this is not an asymmetric center.

<u>Carbon 2</u>

In this carbon, we have an "OH" in the top, an hydrogen in the bottom a carbonyl group in the right, and a CHOH in the left. We have 4 different groups. So, this is an asymmetric center.

<u>Carbon 3</u>

In this carbon, we have an "OH" at the bottom, an hydrogen in the top, a CHOH group in the right (that is bonded to a carbonyl group), and a CHOH in the left. We have 4 different groups. So, this is an asymmetric center.

<u>Carbon 4</u>

In this carbon, we have an "OH" at the top, an hydrogen in the bottom a CHOH group in the right (that is bonded to a CHOH group), and a CHOH in the left. We have 4 different groups. So, this is an asymmetric center.

<u>Carbon 5</u>

In this carbon, we have an "OH" at the bottom, an hydrogen in the top, a CHOH group in the right (that is bonded to a CHOH), and a CH2OH in the left. We have 4 different groups. So, this is an asymmetric center.

<u>Carbon 6</u>

In this carbon, we have two bonds with hydrogens, therefore, we dont have 4 different groups. So, this is not an asymmetric center.

See figure 1

I hope it helps!

4 0
3 years ago
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