The change in energy of the system : -63 J
<h3>Further explanation</h3>
Given
279 J work
216 J heat
Required
The change in energy
Solution
Laws of thermodynamics 1
ΔU=Q+W
Rules :
- receives heat, Q +
- releases heat, Q -
- work is done by a system, W -
- work is done on a system, W +
a gas work on the surrounding : W =-279 J
a gas absorb heat from surrounding : Q = +216 J
Internal energy :
= -279+216
= -63 J
I’m sorry no one helped you with those questions. But could you please be a doll and give me the answer for the multiple-choice questions 1-15. Pleaseee I’m so desperate.?
For alpha and beta decay it does because the proton number changes.
During gamma, there is no change of identity, just energy
KBr + Fs won't make a reaction because KBr is stable with an octet.
Bi+O2 probably won't occur because the O2 has a stable octet as well/
