Given are three married couples.
So, let us assume there are 3 men and 3 women
They are sitting in a row of 6 empty seats
There is a definite order constraint that each woman will sit left to her husband. The first woman gets 3 options to choose from 3 available seats. The second woman has two options left as already one seat is filled by the first woman. The last woman has one option left. So, it is
So, number of ways is 3! = = 6 ways.
Answer:
5/6
Step-by-step explanation:
<em>Dividing fractions:</em>
<em>Step 1: Rewrite the first fraction as it is.</em>
<em>Step 2: Replace the division sign with a multiplication sign.</em>
<em>Step 3: Flip the second fraction.</em>
<em>Step 4: Multiply the fractions and reduce the product if necessary.</em>
Let's use the rule of dividing fractions on your problem.
Step 1: Rewrite the first fraction as it is.
Step 2: Replace the division sign with a multiplication sign.
Step 3: Flip the second fraction.
Step 4: Multiply the fractions and reduce the product if necessary.
To multiply fractions, multiply the numerators together, and multiply the denominators together.
We notice that the greatest common factor of 20 and 24 is 4, so we divide both the numerator and denominator by 4 to reduce the fraction.