Answer:
Attached please find response.
Step-by-step explanation:
We wish to find the area between the curves 2x+y2=8 and y=x.
Substituting y for x in the equation 2x+y2=8 yields
2y+y2y2+2y−8(y+4)(y−2)=8=0=0
so the line y=x intersects the parabola 2x+y2=8 at the points (−4,−4) and (2,2). Solving the equation 2x+y2=8 for x yields
x=4−12y2
From sketching the graphs of the parabola and the line, we see that the x-values on the parabola are at least those on the line when −4≤y≤2.
In order to see the behavior of the line formed from the equations, we write the given equation in general form which is y=mx+b
<span>1.5x + 0.2y = 2.68 --> y= -7.5x + 13.4
</span>
<span>1.6x + 0.3y = 2.98 --> y= -5.33x + 9.93
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<span>They definitely are not parallel lines and do not overlap at all points. Plotting the equations in a graph, an intersection is observed. This intersection most likely is the third option. The lines at (1.6, 1.4).</span>
The answer is a. 2 of the sides are the same and one angle is the same