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yan [13]
3 years ago
12

Can someone help me please

Mathematics
1 answer:
ruslelena [56]3 years ago
6 0

Answer:

Multiplication

Step-by-step explanation:

You would use multiplication to find every combination like 4 entrees x 7 sides x 2 desserts

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Lapatulllka [165]
Could you show a picture so i could understand a little bit better?
6 0
3 years ago
Were would coordinates 8,7 be after a feflection over the x axis
Svet_ta [14]

Answer:

(8, -7)

Step-by-step explanation:

well since it flip over the x-axis only, the 8 stays the same, however, the 7 flips completely to the second quadrant and becomes -7.

Hope this helped and have a amazing day.

3 0
3 years ago
In the figure, m and n are rays.
suter [353]
Is there a picture to go along with this??
4 0
4 years ago
Liz simplified the expression 5x - 3(4 - x) and got 2x -12. Did she simplify the expression correctly? Explain how you know.
Orlov [11]

Answer:

Step-by-step explanation:

Incorrect. She forgot to change the sign while distributing.

5x - 3(4-x) = 5x - 12 + 3x = 8x - 12

5 0
3 years ago
The function C(x)=−20x+1681 represents the cost to produce x items. What is the least number of items that can be produced so th
Reptile [31]

Answer:

<em>The least number of items to produce is 41</em>

Step-by-step explanation:

<u>Average Cost</u>

Given C(x) as the cost function to produce x items. The average cost is:

\displaystyle \bar C(X)=\frac{C(x)}{x}

The cost function is:

C(x) = -20x+1681

And the average cost function is:

\displaystyle \bar C(X)=\frac{-20x+1681}{x}

We are required to find the least number of items that can be produced so the average cost is less or equal to $21.

We set the inequality:

\displaystyle \frac{-20x+1681}{x}\le 21

Multiplying by x:

-20x+1681 \le 21x

Note we multiplied by x and did not flip the inequality sign because its value cannot be negative.

Adding 20x:

1681 \le 21x+20x

1681 \le 41x

Swapping sides and changing the sign:

41x \ge 1681

Dividing by 41:

x\ge 41

The least number of items to produce is 41

8 0
3 years ago
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