<u>Given</u>:
The given figure is a square pyramid.
The side length of the base of the pyramid is 6.6 feet.
The height of the pyramid is 12.672 feet.
We need to determine the volume of the pyramid.
<u>Area of the base:</u>
The area of the base can be determined using the formula,
where a is the side length of the base.
Substituting a = 6.6, we get;
Thus, the area of the base is 43.56 square feet.
<u>Volume of the pyramid:</u>
The volume of the pyramid can be determined using the formula,
where A is the area of the base and h is the height of the pyramid.
Substituting A = 43.56 and h = 12.672, we get;
Thus, the volume of the pyramid is 184 cubic feet.
Answer:
controlled experiment
Step-by-step explanation:
Controlled experiment is a type of experiment in which except for only one variable, everything is kept constant.
The common type of the controlled experiment compares the control group against the experimental group. All the variables are identical between two groups except factor which is being tested.
Big advantage of the controlled experiment is that one can eliminate much of uncertainty about the results.
This is the domain and range for exponential function
You are going to solve this in such a quick, slick way
that you will blink and not believe it. Fasten your seat belt.
Here are the tools you'll need:
-- Volume of a cylinder = (pi) (radius)² (height)
-- Volume of a sphere = (4/3) (pi) (radius)³
Now ... the question says that your cylinder and your sphere
have the same volume. Fine ! So you can immediately write
an equation saying that their volumes are equal.
(pi) (radius)² (height) = (4/3) (pi) (radius)³
Divide each side by pi: (radius)² (height) = (4/3) (radius)³
Divide each side by (radius)² (height) = (4/3) (radius)
Fill in the given height: (6 cm) = (4/3) (radius)
Multiply each side by 3/4 : (6 cm) x (3/4) = radius
I'm pretty sure that you can take over now and find the radius.
Answer: 
Step-by-step explanation:
To polygons are said to be similar if all the corresponding angles of given polygons are equal.
In the given figure, it can be seen that in quadrilateral FSHB and quadrilateral KTWJ all the corresponding angles are equal.
∠F=∠K
∠S=∠T
∠H=∠W
∠B=∠J
Therefore, The given polygons are similar.
Hence,
