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cupoosta [38]
2 years ago
10

Slove 1/4(x-7)+5=7/8x

Mathematics
1 answer:
baherus [9]2 years ago
5 0

Answer: The answer is...9 and 1/2!

Step-by-step explanation: Subtraction of course!

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PLEASE HELP!<br><br> What is AD? <br><br> A. 15 <br><br> B. 12 <br><br> C. 3 <br><br> D. 20
ki77a [65]

Answer:

A. 15

Step-by-step explanation:

To solve this you need to compare the lengths given to you in the question statement.

Because the lines originate from a single point, they're like triangles.  We can easily see a triangle AGF and a triangle ADE, right?

Both triangles are similar triangles, so we can see triangle ADE as a larger version of angle AGF.

They give you the dimension of A F and A E (through A F + F E) to establish a ratio... and they give you A G, asking for A D.

So, A F = 16, A E = 20 (16 + 4), A G = 12.

Since A D is to A G what A E is to A F, we can easily make the following cross-multiplication:

\frac{A D}{A G} = \frac{A E}{A F}

So, A D = (A G * A E)/A F

A D = (12 * 20) / 16 = 15

3 0
3 years ago
19. Write th<br> three fractions that are greater<br> than ; but less than 1.
Rainbow [258]

Questions:

Write any 3 fractions greater than 0 but less than 1.

Answer:

2/3, 3/5, 7/8

Step-by-step explanation:

All proper fractions are greater than 0 but less than 1.

3 0
3 years ago
What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?
Sati [7]

<u>Answer-</u>

<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>

<u>Solution-</u>

The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.

For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.

Here we are given the three vertices of the triangle are  J(-4,-1), K(-4,8) and L(2,8)

If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.

Applying distance formula we get,

JK^2= (-4+4)^2+ (8+1)^2=0+81=81\\\\KL^2= (-4-2)^2+ (8-8)^2=36+0=36\\\\JL^2= (-4-2)^2+(8+1)^2=36+81=117

As,

\Rightarrow 117=81+36

\Rightarrow JL^2=JK^2+KL^2

\Rightarrow \text{JKL is a right angle triangle}

\Rightarrow \angle K=90^{\circ}

Therefore, the vertex at K (-4, 8) is the orthocentre.

3 0
2 years ago
plllllllllllllllllllllllllllllllllllllllllllllllllzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
evablogger [386]

the answer is D

reason: ration of freshmen to sophmores is 17 to 19, for other way around, flip the num ber

7 0
3 years ago
Solve for d 4d &gt; 8 (Please help)
vekshin1

Answer:

d > 2

Step-by-step explanation:

6 0
3 years ago
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