Answer: dot know srry
Step-by-step explanation:
Answer:
0.9177
Step-by-step explanation:
let us first represent the two failure modes with respect to time as follows
R₁(t) for external conditions
R₂(t) for wear out condition ( Wiebull )
Now,

where t = time in years = 1,
n = failure rate constant = 0.07
Also,

where t = time in years = 1
where Q = characteristic life in years = 10
and B = the shape parameter = 1.8
Substituting values into equation 1

Substituting values into equation 2

let the <em>system reliability </em>for a design life of one year be Rs(t)
hence,
Rs(t) = R1(t) * R2(t)
t = 1
![Rs(1) = [e^{-0.07} ] * [e^{-0.0158} ] = 0.917713](https://tex.z-dn.net/?f=Rs%281%29%20%3D%20%5Be%5E%7B-0.07%7D%20%5D%20%2A%20%5Be%5E%7B-0.0158%7D%20%5D%20%3D%200.917713)
Rs(1) = 0.9177 (approx to four decimal places)
The answer would be: 13^3.
This is because 2-4= -2
Then you add -2 to 5 and you would get 3. So the exponent is 3.
I hope this helps :)
Answer:
C. 3,960
Step-by-step explanation:
∆ADB ~ ∆EDC. Therefore,

(substitution)
Solve for x
Cross multiply
5x - 3x = 7,920
2x = 7,920
x = 7,920/2
x = 3,960 meters