Ok let me start it from here.
you are studying about properties of natural numbers or whole number or may be integers.
So , In this Question you have to follow property of addition of integers.
⇒7+3=( You are at the point 7 on the number line or on the tight rope , you are moving (+3) on the right direction.) So you will reach at 7+1+1+1=10
⇒4+2=( You are at the point 4 on the number line or on the tight rope , you are moving (+2) on the right direction.) So you will reach at 4+1+1=6
In first case Cecil has taken total walk of 10 units and in second case Cecil has taken a walk of 10 units.
The first term(a1) is 3
The second term (a2) is obtained by multiplying 3*(-5)
The third term A3 by multiplying 3 * -5 -5 = a2 times -5
Than you go on and one with that
But your answer is
A1=3;an+1=an(-5)
Answer:
0
Step-by-step explanation:
∫ sin²(x) cos(x) dx
If u = sin(x), then du = cos(x) dx.
∫ u² du
⅓ u³ + C
⅓ sin³(x) + C
Evaluate between x=0 and x=π.
⅓ sin³(π) − ⅓ sin³(0)
0
Can you please give me brainiest :D
Squaring a number is the same as multiplying the number by itself <span>(<span><span>64⋅64</span>).</span></span><span> In this case, </span>64<span> squared is </span><span>4096.
</span><span>8<span>r^3</span>−4096+r−8
</span>Subtract 8<span> from </span><span>−4096</span><span> to get </span><span><span>−4104</span>.
</span><span>8<span>r^3</span>−4104+r
</span>Factor<span> the </span>polynomial<span> using the rational </span>roots<span> theorem.
</span><span>(r−8)(8<span>r^2</span>+64r+513)</span>
