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svet-max [94.6K]
3 years ago
13

Use the following balanced equation to answer the question below: 2C₇H₁₄+21O₂→14CO₂+ 14H₂O

Chemistry
1 answer:
Ivanshal [37]3 years ago
3 0

Answer:

The answer to your question is: 516 g of water

Explanation:

                          2  C₇H₁₄  +      21  O₂       →  14  CO₂   +   14   H₂O

                          8 moles     43 moles    

Process

1.- Find the limiting reactant

Ratio theoretical   O₂ / C₇H₁₄ = 21 / 2 = 10.5

Ratio experimental  O₂ / C₇H₁₄   = 43 / 8 = 5.3

As the ratio diminishes the limiting reactant is O₂.    

2.- Calculate the moles of water

                            21 moles of O₂  -------------  14 moles of water

                             43 moles of O₂ ------------    x

                             x = (43 x 14) / 21

                             x = 28.67 moles of water

3.- Calculate the grams of water

Molecular mass of water= 18g

                             18 g ------------------------ 1 mol of water

                              x     ------------------------  28.67 moles of water

                             x = (28.67 x 18) / 1

                             x = 516 g of water

                       

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<u>Explanation:</u>

In a chemical equation, the chemical species are termed as reactants or products.

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Products are defined as the species which are produced in the reaction and are written on the right side of the reaction arrow.

For the given chemical equation:

2C_6H_{14}(l)+19O_2(g)\rightarrow 12CO_2(g)+14H_2O(g)

On the reactant side:

Number of carbon atoms = (6 × 2) = 12

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What is the formula for Water?​
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Answer:

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Explanation:

Formula of the compound:

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Now;

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