Question

Use the following balanced equation to answer the question below: 2C₇H₁₄+21O₂→14CO₂+ 14H₂O

Answer 1

Answer:

The answer to your question is: 516 g of water

Explanation:

                          2  C₇H₁₄  +      21  O₂       →  14  CO₂   +   14   H₂O

                          8 moles     43 moles    

Process

1.- Find the limiting reactant

Ratio theoretical   O₂ / C₇H₁₄ = 21 / 2 = 10.5

Ratio experimental  O₂ / C₇H₁₄   = 43 / 8 = 5.3

As the ratio diminishes the limiting reactant is O₂.    

2.- Calculate the moles of water

                            21 moles of O₂  -------------  14 moles of water

                             43 moles of O₂ ------------    x

                             x = (43 x 14) / 21

                             x = 28.67 moles of water

3.- Calculate the grams of water

Molecular mass of water= 18g

                             18 g ------------------------ 1 mol of water

                              x     ------------------------  28.67 moles of water

                             x = (28.67 x 18) / 1

                             x = 516 g of water